我认为这个问题已被问过一百万次,但我无法在任何地方找到答案。应该很简单。好的,我的.h文件中有一个结构:
struct question{
string programNum;
string programDesc;
string programPoints;
string programInput;
char programQuestion;
};
然后我在.h和.cpp中的参数中启动了函数:
void setQuestionFileName(question q, char fileName){
q.programQuestion = fileName;
}
好的,到目前为止一切顺利。现在主要是我有尝试在programQuestion中存储argv [1]的问题:
char* fileName = argv[count+1];
接下来是:
setQuestionFileName(questions[count],fileName);
cout << questions[count].programQuestion << endl;
我对指针并不是很好,所以如果有人能帮我将char * argv存储到char问题[count] .programQuestion那将是惊人的。谢谢!
答案 0 :(得分:1)
我要发布代码,我认为它可能会更好用。这是.h:
using namespace std;
// Data
struct question{
string programNum;
string programDesc;
string programPoints;
string programInput;
char* programQuestion;
};
void setQuestionFileName(question* q, char* fileName);
void display(question* q);
void display(question* q);
这是.cpp
using namespace std;
void setQuestionFileName(question* q, char* fileName){
strcpy(q->programQuestion, fileName);
}
void display(question* q){
cout << "Description = " << q->programDesc << endl;
cout << "Number of Points = " << q->programPoints << endl;
cout << "Name of Question File = " << q->programQuestion << endl;
}
// Not used or tested yet
int myCompare (const void * a, const void * b ) {
const char *pa = *(const char**)a;
const char *pb = *(const char**)b;
return strcmp(pa,pb);
}
和main.cpp:
using namespace std;
int main(int argc, char* argv[]){ //or char** argv
question* questions[argc-1]; //Array of questions to be filled by loop.
int sizeOfQuestions = argc; //number of questions passed in at run time
int numLines = 0; //number of lines in file
for(int i=0;i<argc;i++){ //Test loop to make sure the command line file names are read in
std::cout << argv[i] << " says hello" << std::endl;
}
for(int count=0;count<sizeOfQuestions-1;count++){ //This loop places the information from the files into structs
//char fileName = argv[count+1];
char* fileName = argv[count+1];
cout << "Problem number: " << count+1 << "\t Working with file " << fileName << endl;
std::fstream questionFile (fileName, std::fstream::in); //Open the file
if(questionFile.good()){
cout << "File Opened" << endl;
setQuestionFileName(questions[count],fileName);
cout << questions[count]->programQuestion << endl;
getline(questionFile,questions[count]->programNum);
getline(questionFile,questions[count]->programDesc);
getline(questionFile,questions[count]->programPoints);
getline(questionFile,questions[count]->programInput);
display(questions[count]);
questionFile.close();
}else{
cout << "Could not open file!!!" << endl;
}
}
return 0;
}
现在的方式,我遇到了分段错误。
答案 1 :(得分:0)
将programQuestion
从char
更改为char*
而且,这个功能
void setQuestionFileName(question q, char fileName){
q.programQuestion = fileName;
}
我认为应该是
void setQuestionFileName(question& q, char* fileName){
strcpy(q.programQuestion, fileName);
}
几乎没有一个只有1个字符的文件。