无法突破嵌套的for循环

时间:2010-01-12 16:57:01

标签: actionscript-3 arrays loops match break

我有以下功能但是尽管使用了break语句,它在数组中找到匹配后似乎没有停止:

private function CheckMatch() {

// _playersList is the Array that is being looped through to find a match

            var i:int;
            var j:int;

            for (i= 0; i < _playersList.length; i++) {

                    for (j= i+1; j < _playersList.length; j++) {
                        if (_playersList[i] === _playersList[j]) {
                            trace("match:" + _playersList[i] + " at " + i + " is a match with "+_playersList[j] + " at " + j);

                            break;

                            } else {
                            // no match
                            trace("continuing...")

                            }
                        }
                    }

                }

4 个答案:

答案 0 :(得分:10)

啊......我明白了。

使用标签,现在可以使用:

private function CheckMatch() {

// _playersList is the Array that is being looped through to find a match

        var i:int;
        var j:int;

     OuterLoop:   for (i= 0; i < _playersList.length; i++) {

                for (j= i+1; j < _playersList.length; j++) {
                    if (_playersList[i] === _playersList[j]) {
                        trace("match:" + _playersList[i] + " at " + i + " is a match with "+_playersList[j] + " at " + j);

                        break OuterLoop;

                        } else {
                        // no match
                        trace("continuing...")

                        }
                    }
                }

            }

答案 1 :(得分:2)

添加一个名为found initialized的bool var为false。

更改循环条件
i < _playersList.length

i < _playersList.length && !found

然后在休息之前,设置found = true

答案 2 :(得分:1)

break一次只能打破一个循环(或切换)。

答案 3 :(得分:0)

我认为还有另一种解决方案,代码更少:

private function checkMatch():void {
    for (var i : int = 0; i < _playerList.length-1; i++) {
        if (_playerList.indexOf(_playerList[i], i+1) > i) {
            break;
        }
    }
}