Question

我开发的应用程序考虑3.5英寸的.xib文件，而不是故事板。
我无法找到任何可以帮助我设计类似于所有屏幕的应用的教程或指南。
我正在使用Xcode 5.0.1
我只开发没有自动布局的普通应用，只有适用于iOS 6和iOS 7 （IPhone）。
下面是截图在不同屏幕上的不同之处。

一个。 iPhone iOS 6模拟器：

B中。 3.5英寸（Ios 6和Ios 7） C. 4.0英寸（Ios 6和Ios 7）

更新：请更新以下答案，也知道4.7和5.5英寸的屏幕。 enter image description here

Answer 1

如果您想检查以编程方式：

FOR Swift

extension UIDevice {

 var iPhoneX: Bool {
    return UIScreen.main.nativeBounds.height == 2436
 }
 var iPhone: Bool {
    return UIDevice.current.userInterfaceIdiom == .phone
 }
 enum ScreenType: String {
    case iPhone4_4S = "iPhone 4 or iPhone 4S"
    case iPhones_5_5s_5c_SE = "iPhone 5, iPhone 5s, iPhone 5c or iPhone SE"
    case iPhones_6_6s_7_8 = "iPhone 6, iPhone 6S, iPhone 7 or iPhone 8"
    case iPhones_6Plus_6sPlus_7Plus_8Plus = "iPhone 6 Plus, iPhone 6S Plus, iPhone 7 Plus or iPhone 8 Plus"
    case iPhoneXR = "iPhone XR"
    case iPhoneX_iPhoneXS = "iPhone X,iPhoneXS"
    case iPhoneXSMax = "iPhoneXS Max"
    case unknown
 }

 var screenType: ScreenType {
    switch UIScreen.main.nativeBounds.height {
    case 960:
        return .iPhone4_4S
    case 1136:
        return .iPhones_5_5s_5c_SE
    case 1334:
        return .iPhones_6_6s_7_8
    case 1792:
        return .iPhoneXR
    case 1920, 2208:
        return .iPhones_6Plus_6sPlus_7Plus_8Plus
    case 2436:
        return .iPhoneX_iPhoneXS
    case 2688:
        return .iPhoneXSMax
    default:
        return .unknown
    }
  }
}

您可以查看：

print("screenType:", UIDevice.current.screenType.rawValue)

检查 Retina（3.5 / 4英寸屏幕）或非视网膜

if ([[UIScreen mainScreen] respondsToSelector:@selector(scale)]) {
    if ([[UIScreen mainScreen] scale] == 2.0) {
       if([UIScreen mainScreen].bounds.size.height == 568){
          // iPhone retina-4 inch
        } else{
         // iPhone retina-3.5 inch
        }
}
else {
    // not retina display
}

更新：

以编程方式检查所有视网膜iPhone ：

if ([[UIScreen mainScreen] respondsToSelector:@selector(scale)]) {
      if ([[UIScreen mainScreen] scale] == 2.0) {

           if([UIScreen mainScreen].bounds.size.height == 667){
             // iPhone retina-4.7 inch(iPhone 6)
           } 
           else if([UIScreen mainScreen].bounds.size.height == 568){
             // iPhone retina-4 inch(iPhone 5 or 5s)
           } 
           else{
            // iPhone retina-3.5 inch(iPhone 4s)
          }
      }
      else if ([[UIScreen mainScreen] scale] == 3.0)
      {
           //if you want to detect the iPhone 6+ only 
           if([UIScreen mainScreen].bounds.size.height == 736.0){
              //iPhone retina-5.5 inch screen(iPhone 6 plus)
           }
           //iPhone retina-5.5 inch screen(iPhone 6 plus)
      }
 }

同时检查此

#define IS_IPHONE_5 (IS_IPHONE && [[UIScreen mainScreen] bounds].size.height == 568.0)
#define IS_IPHONE_6 (IS_IPHONE && [[UIScreen mainScreen] bounds].size.height == 667.0)
#define IS_IPHONE_6_PLUS (IS_IPHONE && [[UIScreen mainScreen] bounds].size.height == 736.0)

它可以帮到你。

快乐的编码。

Answer 2

在prefix.pch

中添加以下行

#define IS_DEVICE_RUNNING_IOS_7_AND_ABOVE() ([[[UIDevice currentDevice] systemVersion] compare:@"7.0" options:NSNumericSearch] != NSOrderedAscending)
#define iPhoneVersion ([[UIScreen mainScreen] bounds].size.height == 568 ? 5 : ([[UIScreen mainScreen] bounds].size.height == 480 ? 4 : ([[UIScreen mainScreen] bounds].size.height == 667 ? 6 : ([[UIScreen mainScreen] bounds].size.height == 736 ? 61 : 999))))

现在在编程中你可以说......

if (IS_DEVICE_RUNNING_IOS_7_AND_ABOVE()) {
    NSLog("This is iOS 7");
} else {
    NSLog("This is iOS 6 or below");
}


if (iPhoneVersion==4) {
    NSLog("This is 3.5 inch iPhone - iPhone 4s or below");
} else if (iPhoneVersion==5) {
    NSLog("This is 4 inch iPhone - iPhone 5 family");
} else if (iPhoneVersion==6) {
    NSLog("This is 4.7 inch iPhone - iPhone 6");
} else if (iPhoneVersion==61) {
    NSLog("This is 5.5 inch iPhone - iPhone 6 Plus.. The BIGGER");
} else {
    NSLog("This is iPad");
}

Answer 3

您可以使用自动布局或代码。在代码中，您可以使用layoutSubviews方法。只需检查视图高度即可发现iPhone 3.5或4英寸并进行设置：

-(void)layoutSubviews
{
    if (self.view.bounds.size.height == 568)
    {
        [self.textField setFrame:CGRectMake(0, 0, 100, 30)];
        //... other setting for iPhone 4inch
    }
    else
    {
        [self.textField setFrame:CGRectMake(0, 0, 100, 30)];
        //... other setting for iPhone 3.5 inch
    }
}

Answer 4

（SWIFT）：

if(DeviceType.IS_IPHONE_4_OR_LESS)
{
//DO THIS 
}
//*********************************************************************
    enum UIUserInterfaceIdiom : Int
    {
        case Unspecified
        case Phone
        case Pad
    }

    struct ScreenSize
    {
        static let SCREEN_WIDTH         = UIScreen.mainScreen().bounds.size.width
        static let SCREEN_HEIGHT        = UIScreen.mainScreen().bounds.size.height
        static let SCREEN_MAX_LENGTH    = max(ScreenSize.SCREEN_WIDTH, ScreenSize.SCREEN_HEIGHT)
        static let SCREEN_MIN_LENGTH    = min(ScreenSize.SCREEN_WIDTH, ScreenSize.SCREEN_HEIGHT)
    }

    struct DeviceType
    {
        static let IS_IPHONE_4_OR_LESS  = UIDevice.currentDevice().userInterfaceIdiom == .Phone && ScreenSize.SCREEN_MAX_LENGTH < 568.0
        static let IS_IPHONE_5          = UIDevice.currentDevice().userInterfaceIdiom == .Phone && ScreenSize.SCREEN_MAX_LENGTH == 568.0
        static let IS_IPHONE_6          = UIDevice.currentDevice().userInterfaceIdiom == .Phone && ScreenSize.SCREEN_MAX_LENGTH == 667.0
        static let IS_IPHONE_6P         = UIDevice.currentDevice().userInterfaceIdiom == .Phone && ScreenSize.SCREEN_MAX_LENGTH == 736.0
        static let IS_IPAD              = UIDevice.currentDevice().userInterfaceIdiom == .Pad && ScreenSize.SCREEN_MAX_LENGTH == 1024.0
    }

Answer 5

您也可以全局定义。

#define isIPHONE5 ([UIScreen mainScreen].bounds.size.height == 568.f)
if(isIPHONE5){

// iphone 5 screen

}else{

// iphone 3.5 screen

}

在Xcode 5.0.1（更新的xcode 6）中为3.5,4.0（更新的4.7和5.5）英寸屏幕开发相同的UI，没有风景，没有iPad，没有故事板

5 个答案: