Question

我有以下几行：

$staticstart = date('Y-m-d',strtotime('last Monday'));
$staticfinish = date('Y-m-d',strtotime('next Saturday'));

我正在使用它们来选择当周的星期一和星期六，但是当它实际上是星期一时，它选择了前一周的星期一，因此显示了2周的数据....我试过这个和它产生无结果：

$staticstart = date('Y-m-d',strtotime('this Monday'));

我错过了什么？有没有更好的方法来找到本周的星期一和星期六（日期）？

Answer 1

你为什么不这样做呢？

//check the current day
if(date('D')!='Mon')
{    
 //take the last monday
  $staticstart = date('Y-m-d',strtotime('last Monday'));    

}else{
    $staticstart = date('Y-m-d');   
}

//always next saturday

if(date('D')!='Sat')
{
    $staticfinish = date('Y-m-d',strtotime('next Saturday'));
}else{

        $staticfinish = date('Y-m-d');
}

Answer 2

快捷键：

  $start = (date('D') != 'Mon') ? date('Y-m-d', strtotime('last Monday')) : date('Y-m-d');
  $finish = (date('D') != 'Sat') ? date('Y-m-d', strtotime('next Saturday')) : date('Y-m-d');

Answer 3

$staticstart = (today == monday ? date('Y-m-d', today) : date('Y-m-d', strtotime('last monday'));

Answer 4

      $week_number  = date("W", strtotime('now'));// ISO-8601 week number
      $year_number  = date("o", strtotime('now'));// ISO-8601 year number

      // as per  ISO-8601 specification, December 28th is always in the last week of its year.  The highest week number in a year is either 52 or 53.
      // and January 4th always be in the first week of the year
      // and week 01 is the week with the first Thursday in it 
      // Week number according to the ISO-8601 standard, weeks starting on Monday. The first week of the year is the week 
      // N ISO-8601 numeric representation of the day of the week (added in PHP 5.1.0) 1 (for Monday) through 7 (for Sunday)
      // w Numeric representation of the day of the week 0 (for Sunday) through 6 (for Saturday)

    // PHP week start from 0 = sunday to 6 saturday 
    // $sunday_last_week = date("Y-m-d", strtotime('sunday last week'));  
    // $sunday_this_week = date("Y-m-d", strtotime('sunday this week'));

    // echo "sunday last week: $sunday_last_week - sunday this week: $sunday_this_week";


    if($week_number<=9)
    {
      $week_number= "0".$week_number; 
    }
    $last_monday = date('Y-m-d', strtotime("$this_year-W$week_number")); 
    // print date of first day of week (MONDAY), week_number must be two digit and year must be 4 digit ISO 8601


    $tuesday= date('Y-m-d',strtotime("$last_monday +1 days"));
    $wednesday= date('Y-m-d',strtotime("$last_monday +2 days"));
    $thursday= date('Y-m-d',strtotime("$last_monday +3 days"));
    $friday= date('Y-m-d',strtotime("$last_monday +4 days"));
    $saturday= date('Y-m-d',strtotime("$last_monday +5 days"));

    $next_sunday= date('Y-m-d',strtotime("$last_monday +6 days"));

  ?>

Answer 5

获取当前星期之间的日期范围

$monday = strtotime("last monday");
$monday = date('w', $monday)==date('w') ? $monday+7*86400 : $monday;

$sunday = strtotime(date("Y-m-d",$monday)." +6 days");

$this_week_start = date("Y-m-d",$monday);
$this_week_end = date("Y-m-d",$sunday);

echo "Current week range from $this_week_start to $this_week_end ";

Answer 6

我认为这是一个更简单的解决方案

$monday = date('Y-m-d', strtotime('monday this week'));
$saturday = date('Y-m-d', strtotime('saturday this week'));

STRTOTIME查找当前周，周日和周六的日期，PHP

6 个答案: