Question

如何在jqgrid中添加时间选择器字段...这是我的代码在这里如何添加在jqgrid中提交的时间选择器

这些是导入文件

<link rel="stylesheet" href="css/redmond/jquery-ui.css">    
<link rel="stylesheet" href="css/redmond/jquery.ui.theme.css">
<link rel="stylesheet" href="css/ui.jqgrid.css">

  <link rel="stylesheet" href="css/redmond/jquery-ui-timepicker-addon-1.4.3.css">
 <script src="js/jquery.jqGrid.min.js" type="text/javascript"></script>
<script src="js/jquery.js" type="text/javascript"></script>
<script src="js/jquery.min.js" type="text/javascript"></script>
<script src="js/jquery.jqGrid.src.js" type="text/javascript"></script>
<script src="js/grid.locale-en.js" type="text/javascript"></script>    
<script src="js/grid-search.js" type="text/javascript"></script>
<script src="js/jquery-ui.min.js" type="text/javascript"></script>  
    <script src="jquery-ui-timepicker-addon-1.4.3.js" type="text/javascript"></script>


{name:'joinDate',index:'joinDate',width:4.5,
            editable:true,editoptions:{size:12,
                dataInit:function(elem){
                $(elem).datetimepicker({dateFormat: 'dd-mm-yy',
                    timeFormat: 'H:mm',});
                },
        defaultValue: function(){
                var currentTime = new Date();
                var month = parseInt(currentTime.getMonth() + 1);
                month = month <= 9 ? "0"+month : month;
                var day = currentTime.getDate();
                day = day <= 9 ? "0"+day : day;
                var year = currentTime.getFullYear();
                return year+"-"+month + "-"+day;                
                }},
                editrules:{required:true},
            formatoptions: {srcformat:'ISO8601Long', newformat:'d-M-y H:i'}},

任何人请回复我

谢谢你

Answer 1

您可以使用jQuery UI插件Timepicker，例如，它允许实现纯timepicker或datetimepicker。您只需将$(el).datepicker的使用情况替换为$(el).datetimepicker，并添加datetimepicker的选项。

The demo例如我为the demo创建的the answer的小修改。它演示了如何使用datetimepicker。

如何在jqgrid中编写时间选择器字段

1 个答案: