Question

我最终遇到了一个奇怪的问题。我无法找出问题的根本原因。请帮忙。

请执行以下脚本

创建一个表格

CREATE TABLE Employee_salary (ID INT,emp_name VARCHAR(50),Salary INT)

INSERT INTO Employee_salary VALUES(1,'Dolu',15000)
INSERT INTO Employee_salary VALUES(2,'Bolu',15000)
INSERT INTO Employee_salary VALUES(3,'Kalia',10000)
INSERT INTO Employee_salary VALUES(4,'Bheem',50000)
INSERT INTO Employee_salary VALUES(5,'Krishna',40000)
INSERT INTO Employee_salary VALUES(6,'Chutki',30000)

SELECT * FROM Employee_salary

ID  emp_name    Salary
1   Dolu        15000
2   Bolu        15000
3   Kalia       10000
4   Bheem       50000
5   Krishna     40000
6   Chutki      30000

我想要最高薪水的员工，所以我找到了bwlow查询

SELECT Top 1 emp_name,MAX(salary) from Employee_salary  Group by emp_name

我试图找到最低薪水员工并尝试通过将'MAX'更改为'MIN'来执行以下查询。令人惊讶的是，以下查询无论如何都不起作用。它仍显示'Bheem，50000'，这是一个错误的答案。任何人都可以告诉我这个问题的原因或原因。

SELECT Top 1 emp_name,MIN(salary) from Employee_salary  Group by emp_name

Answer 1

请从最低薪水中尝试以下查询：

SELECT Top 1 emp_name, salary from Employee_salary order by salary

和

SELECT Top 1 emp_name, salary from Employee_salary order by salary desc

获得最高薪水。

如果有多个员工的薪水相同，请尝试：

SELECT Top 1 WITH TIES emp_name, salary from Employee_salary order by salary desc

Answer 2

尝试下面查询最低和最高工资记录。

-- For Max
SELECT emp_name, salary from Employee_salary where salary = (SELECT Max(salary) from Employee_salary)

-- For Min
SELECT emp_name, salary from Employee_salary where salary = (SELECT Min(salary) from Employee_salary)

Answer 3

可能有多个行具有相同的最高工资和最低工资。所以下面的查询就可以实现这个

select s1.emp_name, s1.Salary from Employee_salary as s1 where not exists(select * from Employee_salary as s2 where s2.Salary > s1.Salary);

select s1.emp_name, s1.Salary from Employee_salary as s1 where not exists(select * from Employee_salary as s2 where s2.Salary < s1.Salary);

Answer 4

薪水最高的员工

SELECT MAX(salary) from Employee_salary

这将显示员工的最高薪水

如果您想查看员工详细信息，请

SELECT MAX(salary), Employee_salary.* from Employee_salary

如果您需要最低工资，则需要添加MIN() MAX()

最低工资的员工sql服务器 - 不使用MIN功能

4 个答案: