尝试telnet到Brocade路由器并且python脚本发送错误....不确定这里有什么问题。尝试过调试，但无法使其正常工作。我相信这是一个及时的问题。如果有人建议如何让它发挥作用我感激不尽。
注意：这是Python 3.0
import getpass
import sys
import telnetlib
HOST = "1.1.1.1"
user = "admin"
password = "password"
port = "23"
telnet = telnetlib.Telnet(HOST)
telnet.read_until("sw0 login:,3")
telnet.write(admin + "\r")
if password:
telnet.read_until("Password: ")
telnet.write(password + "\n")
tn.write("term len 0" + "\n")
telnet.write("sh ver br\n")
telnet.write("exit\n")
ERROR:
Traceback (most recent call last):
File "C:\Users\milan\Desktop\telnetNew.py", line 13, in <module>
telnet.read_until("Username :,3")
File "C:\Python33\lib\telnetlib.py", line 299, in read_until
return self._read_until_with_select(match, timeout)
File "C:\Python33\lib\telnetlib.py", line 352, in _read_until_with_select
i = self.cookedq.find(match)
TypeError: Type str doesn't support the buffer API
This is my prompt after logging manually using telnet port 23 and this is what i expected command to work.
_________________________________________________________________________________
Network OS (sw0)
xxxxxxxxxx
sw0 login: xxxxx
Password: xxxxx
WARNING: The default password of 'admin' and 'user' accounts have not been changed.
Welcome to the Brocade Network Operating System Software
admin connected from 10.100.131.18 using console on sw0
sw0# sh ver
sw0#
答案 0 :(得分：5)
在查看文档时，似乎telnetlib需要bytestr，而不是Str。所以尝试这个。，它应该将所有内容转换为字节而不是Str
import sys
import telnetlib
HOST = "1.1.1.1"
user = "admin"
password = "password"
port = "23"
telnet = telnetlib.Telnet(HOST,port)
telnet.read_until(b"login: ")
telnet.write(admin.encode('ascii') + b"\n")
telnet.read_until(b"Password: ")
telnet.write(password.encode('ascii') + b"\n")
tn.write(b"term len 0\n")
telnet.write(b"sh ver br\n")
telnet.write(b"exit\n")
- 编辑 - 我安装了python并尝试对付我的一个路由器。将用户名/密码更改为我的凭据我能够正常登录。 （我删除了密码检查和getpass，因为它们没有被使用，因为你的代码是硬编码的）。看起来你复制了2.x示例，但3.x要求缓冲区兼容的没有b“我得到这个
Traceback (most recent call last):
File "foo.py", line 5, in <module>
telnet.read_until("login: ")
File "/usr/local/Cellar/python32/3.2.5/Frameworks/Python.framework/Versions/3.2/lib/python3.2/telnetlib.py", line 293, in read_until
return self._read_until_with_poll(match, timeout)
File "/usr/local/Cellar/python32/3.2.5/Frameworks/Python.framework/Versions/3.2/lib/python3.2/telnetlib.py", line 308, in _read_until_with_poll
i = self.cookedq.find(match)
TypeError: expected an object with the buffer interface
用b“我得到
[~] /usr/local/bin/python3.2 foo.py
b'\r\n\r\nThis computer system including all related equipment, network devices\r\n(specifically including Internet access), are provided only for\r\nauthorized use. All computer
表明它正在运作..你现在有什么错误
答案 1 :(得分：2)
import telnetlib , socket
class TELNET(object):
def __init__(self):
self.tn = None
self.username = "root"
self.password = "12345678"
self.host = "10.1.1.1"
self.port = 23
self.timeout = 5
self.login_prompt = b"login: "
self.password_prompt = b"Password: "
def connect(self):
try :
self.tn = telnetlib.Telnet(self.host,self.port,self.timeout)
except socket.timeout :
print("TELNET.connect() socket.timeout")
self.tn.read_until(self.login_prompt, self.timeout)
self.tn.write(self.username.encode('ascii') + b"\n")
if self.password :
self.tn.read_until(self.password_prompt,self.timeout)
self.tn.write(self.password.encode('ascii') + b"\n")
def write(self,msg):
self.tn.write(msg.encode('ascii') + b"\n")
return True
def read_until(self,value):
return self.tn.read_until(value)
def read_all(self):
try :
return self.tn.read_all().decode('ascii')
except socket.timeout :
print("read_all socket.timeout")
return False
def close(self):
self.tn.close()
return True
def request(self,msg):
self.__init__()
self.connect()
if self.write(msg) == True :
self.close()
resp = self.read_all()
return resp
else :
return False
telnet = TELNET()
#call request function
resp = telnet.request('ps www') # it will be return ps output
print(resp)
答案 2 :(得分：2)
这些答案中的大多数都是非常深入的解释，我发现它们有点难以理解。简短的回答是Python 3x站点上的示例代码错误。
解决这个问题，而不是 'telnet.read_until（“用户名：，3”）' 使用 'telnet.read_until（b“用户名：，3”）'
答案 3 :(得分：1)
与其他答案一样，问题是Telnetlib需要字节字符串。在Python 2中，str类型是一个字节字符串（一串二进制数据），而它是Python 3中的一个unicode字符串，另一个表示二进制数据的新bytes类型是{{1在Python 2中做过。
这样做的结果是，在Python 3中使用Telnetlib时，您需要将str数据转换为str数据。我有一些代码可以在Python2和Python3中使用，我认为值得分享。
bytes然后，您实例化新的class Telnet(telnetlib.Telnet,object):
if sys.version > '3':
def read_until(self,expected,timeout=None):
expected = bytes(expected, encoding='utf-8')
received = super(Telnet,self).read_until(expected,timeout)
return str(received, encoding='utf-8')
def write(self,buffer):
buffer = bytes(buffer, encoding='utf-8')
super(Telnet,self).write(buffer)
def expect(self,list,timeout=None):
for index,item in enumerate(list):
list[index] = bytes(item, encoding='utf-8')
match_index, match_object, match_text = super(Telnet,self).expect(list,timeout)
return match_index, match_object, str(match_text, encoding='utf-8')
类而不是Telnet。新类重写了Telnetlib中的方法，以执行从telnetlib.Telnet到str和bytes到bytes的转换，以便问题消失。
当然，我只是覆盖了我正在使用的方法，但是从示例中应该清楚如何将这个想法扩展到其他方法。基本上，你需要使用
str和
bytes(str_string, encoding='utf-8')
我的代码是有效的Python 2和3，因此可以使用任何解释器进行修改。在Python2中，会跳过覆盖方法的代码，实际上会被忽略。如果您不关心向后兼容性，则可以删除检查Python版本的条件。