Question

我正在尝试制作一场战争纸牌游戏。每位玩家一次抽取1张牌，每张牌最多26张。现在我需要将卡的字符串值转换为整数，以便我可以使用它们来确定谁有更高的牌。这是我的第一个使用数组的程序，我在这个程序中遇到了很多问题。我该怎么做呢？

编辑：如果不清楚，我问如何从String []数字中获取int值而无需手动分配任何值。为了看谁赢得每手牌，我需要比较一下。

import java.util.ArrayList;
import java.util.Random;

public class Card {
    String finalCard = "";
     int suit, number;
    String [] suits = {"Heart" , "Diamond" , "Spade" , "Club"}; //suits
    String [] numbers = { "2" , "3" , "4" , "5" , "6" , "7" , "8" , "9" , "10" , "Jack" , "Queen" , "King" , "Ace" }; //card values
    String card = "";
    public Card() {

    }
     public Card(int suits, int numbers)
        {
            suit = suits; 
            number = numbers;
        }


    public String toString()
        {
            String finalCard = numbers[number] + " of " + suits[suit];
            return finalCard;        
        }
    }

import java.util.ArrayList;
import java.util.Random;

public class FullDeck {
    private ArrayList<Card> cards = new ArrayList<Card>();//card array list

        public FullDeck()
        {   
            for(int a =0; a<=3; a++) //loops through suits
            {
                for(int b =0; b<=12;b++) //loops through values
                {
                    cards.add(new Card(a,b)); //creates adds cards to list
                }

            }

        }

        public Card drawRandomCard()
        {
            Random generator = new Random(); //picks random card
            int index = generator.nextInt(cards.size());
            return cards.remove(index); //removes card from list
        }

        public String toString()
        {
            String result = "Cards remaining in deck: " + cards; //not currently used
            return result;
        }    
    }
import java.applet.Applet;
import java.awt.Container;
import java.awt.FlowLayout;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import java.util.Scanner;
import javax.swing.*;

public class WarUI extends JApplet
    implements ActionListener {
        JTextArea displayLabel = new JTextArea(""); //sets label to display message
        JButton runButton = new JButton("Run"); //button that starts program
        Container con = getContentPane(); //gets container


        Card player1;
        Card player2;
        FullDeck hand1 = new FullDeck();

        Card card = new Card();


        public void init() {
            con.setLayout(new FlowLayout());//sets flowlayout
            con.add(new JLabel());      //jlabel container
            con.add(runButton);  //run button container
            con.add(displayLabel); //display label container
            runButton.addActionListener(this);//looks to see if run is clicked
           }

        public void actionPerformed(ActionEvent e) {


            for (int i = 0; i < 1; i++) {
                player1= hand1.drawRandomCard(); //draws cards for player 1
                player1.toString();
                }
            for (int i = 0; i < 1; i++) {
                player2= hand1.drawRandomCard(); //draws cards for player 2
                player2.toString(); 
                }

            displayLabel.setText(player1.toString() + "\n" + player2.toString()  ); //displays both players values/suits
                }
        }

Answer 1

首先在Card类中使套装和数字静止。因为每次创建卡时阵列始终保持不变并且不必初始化。虽然你必须在Card类中添加getters到变量suit和number。

要检查哪张卡更高，首先必须检查哪个数字索引更高，然后检查卡的套装索引。

Card card1 = ...
Card card2 = ...

if(card1.getnumber() < card2.getnumber())
{
    //card1 is lower
}else if(card1.getnumber() > card2.getnumber()){
    //card2 ist lower
}else{
    if(card1.getsuit() < card2.getsuit()){
        //card1 is lower
    }else if(card1.getsuit() > card2.getsuit()){
        //card2 is lower
    }else{
        // Both Cards are the same
    }
}

请记住，使用此实现，suit数组的顺序很重要

Answer 2

要将String对象转换为原始int，只需使用Integer.parseInt()方法，如下所示：

String card1="12";
String card2="20";

int Card1=Integer.parseInt(card1);     
int Card2=Integer.parseInt(card2);

if(Card1>Card2)
{
    System.out.println("You Win!");
}

如何从纸牌游戏字符串数组中获取int值

2 个答案: