稍微有点代码问题。我想使用一个延迟,以便用户在点击正确的按钮后看到gui一段有限的时间,然后它将重置回原来的形式。我试图使用thread.sleep()代码执行此操作,但在编译器中不断出现异常错误。我想也许可以使用摆动计时器,但不知道这是否可行。非常感谢有关正确行动方案的任何反馈。
import java.awt.*;
import javax.swing.*;
import java.util.*;
import java.awt.event.*;
import java.lang.Thread;
public class Test extends JFrame implements ActionListener {
JLabel label1, label2, label3;
ImageIcon image1, image2, image3, image4, image5;
JTextField textResult;
JButton [] buttons;
int treasureLocation;
int clicks = 0;
Thread td = new Thread(); //Declare thread
public static void main(String[] args) {
new Test();
}
public Test (){
this.setSize(700,700);
this.setLocationRelativeTo(null);
this.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
this.setTitle("Treasure Hunt Game");
JPanel thePanel = new JPanel();
thePanel.setLayout(new GridLayout(0,3,0,0));
image1 = new ImageIcon(getClass().getResource("Treasure.jpg"));
image2 = new ImageIcon(getClass().getResource("Pirate.jpg"));
image3 = new ImageIcon(getClass().getResource("sand2.jpg"));
image4 = new ImageIcon(getClass().getResource("emptyhole.jpg"));
image5 = new ImageIcon(getClass().getResource("map.jpg"));
label1 = new JLabel("Click the buttons!");
label1.setFont(new Font("Serif", Font.PLAIN, 20));
label1.setForeground(Color.red);
label2 = new JLabel(image5);
label3 = new JLabel(image2);
buttons = new JButton[9];
buttons[0] = new JButton(image3);
buttons[1] = new JButton(image3);
buttons[2] = new JButton(image3);
buttons[3] = new JButton(image3);
buttons[4] = new JButton(image3);
buttons[5] = new JButton(image3);
buttons[6] = new JButton(image3);
buttons[7] = new JButton(image3);
buttons[8] = new JButton(image3);
thePanel.add(buttons[0]);
thePanel.add(buttons[1]);
thePanel.add(buttons[2]);
thePanel.add(buttons[3]);
thePanel.add(buttons[4]);
thePanel.add(buttons[5]);
thePanel.add(buttons[6]);
thePanel.add(buttons[7]);
thePanel.add(buttons[8]);
thePanel.add(label1);
thePanel.add(label2);
thePanel.add(label3);
buttons[0].addActionListener(this);
buttons[1].addActionListener(this);
buttons[2].addActionListener(this);
buttons[3].addActionListener(this);
buttons[4].addActionListener(this);
buttons[5].addActionListener(this);
buttons[6].addActionListener(this);
buttons[7].addActionListener(this);
buttons[8].addActionListener(this);
this.add(thePanel);
this.setVisible(true);
treasureLocation = new Random().nextInt(buttons.length);
System.out.println(treasureLocation);
}
public void actionPerformed(ActionEvent evt){
Object source = evt.getSource();
if (source == buttons[treasureLocation]) {
buttons[treasureLocation].setIcon(image1);
label1.setText("You've found me Treasure!");
td.sleep(3000); //Delay and reset code
Test.this.setVisible(false);
Test.this.dispose();
new Test();
}
else
{
((JButton)source).setIcon(image4);
}
clicks++;
System.out.println(clicks);
if (clicks == 5){
label1.setText("One more try Matey!");
}
if ((clicks == 6) && (source != buttons[treasureLocation])) {
label1.setText("Game over!");
}
if (clicks == 7){
Test.this.setVisible(false);
Test.this.dispose();
new Test();
}
}
}
答案 0 :(得分:4)
线程休眠将整个GUI置于睡眠状态,包括绘制,因此永远不要在Swing事件线程上使用它。改为使用Swing Timer。
我还建议不要显示新的JFrame或GUI,因为向用户投掷多个窗口会让人讨厌。
如,
public void actionPerformed(ActionEvent e) {
final Object source = evt.getSource();
if (source == buttons[treasureLocation]) {
buttons[treasureLocation].setIcon(image1);
label1.setText("You've found me Treasure!");
Timer timer = new Timer(TIMER_DELAY, new ActionListener() {
public void actionPerformed(ActionEvent evt) {
// reset GUI including the JButton's icon
}
});
timer.setRepeats(false);
timer.start();
}
}
有关详细信息,请查看Swing Timer Tutorial。