Question

我正在尝试让我的程序正确读取我的输入文件，以下是我的输入文件，第一列是我希望用户输入的，然后需要从相应的行中取出值，值被阅读是错误的。

14,14,8,4.4,16,2.0,1.7,7,4.7,0.23,0.44,290,350

16,16,10,0.5,17,2.2,1.8,8,4.4,0.27,0.5,310,370

18,18,11,0.5,18,2.2,2.0,9,6.0,0.30,0.56,320,380

20,20,12,0.5,19,2.3,2.2,9.5,6.4,0.32,0.59,330,390

22,22,13,0.5,20,2.4,2.4,10,6.7,0.33,0.63,340,410

<24> 24,24,0.5,21,2.5,2.5,11,7.4,0.37,0.69,350,420

27,27,16,0.6,22,2.6,2.8,11.5,7.7,0.38,0.72,370,450

30,30,18,0.6,23,2.7,3.0,12,8.0,0.40,0.75,380,460

35,35,21,0.6,25,2.8,3.4,13,8.7,0.43,0.81,400,480

40,40,24,0.6,26,2.9,3.8,14,9.4,0.47,0.88,420,500

45,45,27,0.6,27,3.1,3.8,15,10.0,0.50,0.94,440,520

50,50,30,0.6,29,3.2,3.8,16,10.7,0.53,1.00,460,550

    ifstream soft;
    soft.open ("Softwood.txt"); //Opens the softwood text file which holds the values required for calculations 

cout <<"Please enter the strength class of the timber, excluding the letter." <<endl; 
cin >> type;

float a [12][13]; //begins the array so the input file can be read

int i, j;

for (i=0; i<12; i++)
{
    for (int j=0; j<13; j++)
        soft>>a[i][j];
}


int m=0;

while(a[m][0]!= type && m<12)
 {
m++;
 }
bendingStrength = a[m][1];
tensionParallel = a[m][2];
tensionPerpindicular = a[m][3];
compressionParallel = a[m][4];
compressionPerpindicular = a[m][5];
shearStrength = a[m][6];
elasticityParallel = a[m][7];
elasticityParallelFive = a[m][8];
elasticityPerpindicular = a[m][9];
shearModulus = a[m][10];
density = a[m][11];
meanDensity = a[m][12];

Answer 1

while(a[m][0]!= type && m<12)
 { 
m++;
 }

如果m == 11，程序会增加m的值（现在m == 12），并尝试将a [12] [i]的值（对于i在1到12之间）赋值给对象。但是在C ++中的数组中，我们从0开始计算对象的数量，因此数组中的最大数字是[11] [12]。您的程序尝试读取不存在的对象的值。

Answer 2

您应该在阅读文件时忽略逗号。它可以像这样完成：

for (i=0; i<12; i++)
{
    for (int j=0; j<13; j++)
    {
       soft >> a[i][j];
       char ch;
       soft.get(ch);
       if(ch != ',')
           soft.unget();
    }
}

试图让我的程序正确读取输入文件2d数组

2 个答案: