如何在密码中显示计数：

Question

for attempt in range(5):                        
    password = input("Password: ")              
    if password == "changeme":
        print("Thou Shall Pass Into Mordor")
        break
else:
    print("Thou Shall Not Pass Into Mordor")

我需要帮助，因此会显示尝试密码，如下所示：

  

密码（1次尝试）：

Answer 1

您的attempt变量包含尝试次数。将它与for循环中的print语句连接起来。

修改：删除添加1，没有必要。

Answer 2

password_attempt = 0
for attempt in range(5):                        
    password = input("Password: ")              
    if password == "changeme":
        print("Thou Shall Pass Into Mordor")
        break
else:
    password_attempt += 1
    print("Thou Shall Not Pass Into Mordor")
    print(Password(%s attempt(s)) %password_attempt

Answer 3

我只是对您发布的代码进行了一些更改，以满足您的需求。

for attempt in range(1, 5):                                # Change range to be 1 - 5.
    password = input("Password (%d attempts): " % attempt) # Change input message showing attempt number.             
    if password == "changeme":
        print("Thou Shall Pass Into Mordor")
        break
else:
    print("Thou Shall Not Pass Into Mordor")