pthread_join后的分段错误

时间:2013-12-09 19:22:50

标签: c ubuntu segmentation-fault pthreads pthread-join

我正在尝试使用c在ubuntu中使用多个线程来计算pi的值。 我不完全熟悉pthread_create和pthread_join应该作为输入获得的变量,以及如何处理类型'void'。 我在代码中种植了一些printf以找到问题的根源,显然问题出在main()中最后一个'for循环'的'pthread_join'中

这是我的代码:

#include <time.h>
#include <stdlib.h>
#include <stdio.h>
#include <math.h>
#include <assert.h>
#include <pthread.h>

void* drawpoints (void* arg)
{
    int i;
    int* counter;
    double x,y,dist; /*coordinates of point*/
    int* n = arg;
    *counter = 0;
    srand(time(NULL));
    for (i = 0; i<*n; i++)
    {
        /*square is of size 1X1 - 0<=x,y<=1 -> radius = 0.5*/
        x = (double)rand()/(double)RAND_MAX;
        y = (double)rand()/(double)RAND_MAX;
        /*0.5 is the center of circle*/
        dist = sqrt(pow(x-0.5,2)+pow(y-0.5,2));
        if (dist<0.5)
        {
            *counter++;
        }
/*      printf("x = %f\ny = %f\ndist = %f\ncounter = %d\n\n",x,y,dist,*counter);*/
    }
    return (void*)counter;

}    
int main (int argc, char** argv)
{
    assert(argc == 3);

    int rc;
    int totalThreads,n,i,counter,numDots;
    void* currPtr;
    int* curr;
    pthread_t* p_list = (pthread_t*)malloc(sizeof(pthread_t)*atoi(argv[2]));
    n = atoi(argv[1]);
    totalThreads = atoi(argv[2]);
    numDots = n/totalThreads;
    for (i = 0; i<totalThreads; i++)
    {
        rc = pthread_create(&(p_list[i]), NULL, drawpoints, &numDots); assert(rc == 0);    
    }
    for (i = 0; i<totalThreads; i++)
    {
        printf("%lu\ntry\n\n",p_list[i]);
        rc = pthread_join(p_list[i], &currPtr); assert(rc == 0);
        curr = currPtr;
        counter+=(*curr);
    }
    printf("%f\n\n",(double)counter/n*4);
    free(p_list);
    return 0;

}

这是我在终端中获得的日志:

3079416688
try

Segmentation fault

2 个答案:

答案 0 :(得分:1)

来自您的函数drawpoints

int* counter; //You don't allocate memory for this int
double x,y,dist; /*coordinates of point*/
int* n = arg
*counter = 0; //yet here you assign 0 to a unknown memory location 

因此,在你取消引用计数器之前,你必须运行这样的东西:

int* counter = malloc(sizeof(int));

并检查是否couter!= NULL。

除了你需要确保你在使用后也释放它。

答案 1 :(得分:1)

在“drawpoints”函数中,您返回“计数器”指针而不向其分配任何内存。 并且在主要的类型转换中指向int指针的void指针。 像这样

int* counter=NULL;
counter = (int *)malloc(sizeof(int));
if(NULL == count)
 return -1;

//typecast
curr = ((int *)currPtr);