Question

我想解析一个字符串并替换该字符串中的某些字符，我尝试使用分隔符，但它无法正常工作。

这是我要解析的字符串：

chartData = [T44E-7    | x   |G-7    | x   |
Bb^7    | x   |Bh7    |E7#9    |A-7    | x   |F#h7    | x   |F-7    | x Q  |C-7    | x   |B7#9    | x  Z        Y{QC-7    | x   |Ab^7    | x  }

这是我想要的最终结果：

[T44E-7    | x   |G-7    | x   |

|  Bb^7    | x   |Bh7    |E7#9 |

|A-7       | x   |F#h7   | x   |

|F-7       | x Q |C-7    | x   |

|B7#9      | x   ||        

|:QC-7     | x   |Ab^7    | x  :|

我还想将％，Z替换为||，{with |：和}替换为：|。

这是我的解析函数：

void parseChartData(string chartDataString){
    string token;
    if(!chartDataString.empty()){ 
         chartData.clear();
         chartData.append(chartDataString);
         string delimiter = "|";
         int pos = 0;
         while ((pos = chartData.find(delimiter)) != pos) {
             token = chartData.substr(0,pos);
             cout << token << endl;
         }
    }
}

Answer 1

我认为第一个解决方案是这个。

int occurrencies = 0;    // number of "|" found
int curPos = 0;
int startPos = 0;
string delimiter = "|";
// find the next delimiter from the last one found, not from the beginning of chartData
while ((pos = chartData.find(delimiter, curPos)) != string::npos) {
    curPos = pos+1;
    occurrencies++;

    // print something only if 4 delimiters have been found
    if (occurrencies%4 == 0) {
        // print the part from the last character printed to the last delimiter found
        string part = chartData.substr(startPos,pos-startPos);
        cout<<part<<endl;
        // after printing, the last character printed become the beginning of the next token
        startPos = pos+1;
    }
}

// at the end print the remaining part of chartData
string lastPart = chartData.substr(startPos,string.size()-startPos);
cout<<lastPart<<endl;

应该有效

如何解析字符串并替换字符串的某些字符？

1 个答案: