我可以使用平滑的小补间更改文本的值,但每次我清空一个svg并创建一个新的svg。这最终会使用空SVG加载DOM。我怎么能摆脱他们?
D3:
var vis = d3.select("#visualisation"),
commasFormatter = '$' + d3.format(",.0f"),
numVis = d3.select("#defecit"),
defTotal = d3.select("#defense");
function init () {
//Initialize mean text
numVis.append("text")
.attr("id", "meantext")
.attr("y", 40)
.attr("x", 118)
.style("font-size", "26px")
.style("font-family","Arial, Helvetica, sans-serif")
.style('font-weight', 'bold')
.style('text-color', '#525252');
defTotal.append("text")
.attr("id", "defense")
.attr("y", 0)
.attr("x", 0)
.style("font-size", "16px")
.style("font-family","Arial, Helvetica, sans-serif")
.style('font-weight', 'bold')
.style('text-color', '#525252');
d3.select("#meantext")
.transition()
.duration(500)
.ease('linear')
.tween("text", function() {
var i = d3.interpolate(this.textContent, dollars.value);
return function(t) {
this.textContent = '$' + d3.format(",")(Math.round(i(t)));
};
})
//Doing something like this didn't work - kept giving me an error that the object array had no exit function
d3.select("meantext").exit().remove()
}
答案 0 :(得分:1)
您可以删除特定元素,执行d3.select("#idOfElement").remove()
。 1}}此处不需要匹配和绑定数据。