我有一张表格,格式为
propertyvaluestrings
userSignedwww.website.com.brxxx /销售/卖
www.website.comuser /卖
www.website.com.co.uk \暂停营业税
我需要做的是按照下面的sql的网站列进行分组,以获得每个网站的总计
SELECT top 1000
CASE
WHEN propertyvaluestrings LIKE '%www.website.co.uk%' THEN 'UK'
WHEN propertyvaluestrings LIKE '%www.website.us%' THEN 'USA'
WHEN propertyvaluestrings LIKE '%www.website.com.br%' THEN 'Brazil'
WHEN propertyvaluestrings LIKE '%www.website.co.id%' THEN 'indonesia'
WHEN propertyvaluestrings LIKE '%www.website.com%' THEN 'Global'
ELSE 'XXXXXXXXXXXXXXXX----Unknown'
END as Site
,
PropertyValueStrings
FROM profiles
答案 0 :(得分:1)
您的意思是计算每个国家/地区的PropertyValueStrings数量吗?如果是这样,这应该有效:
SELECT Site, COUNT(*) AS Count
FROM (
SELECT (CASE
WHEN propertyvaluestrings LIKE '%www.website.co.uk%' THEN 'UK'
WHEN propertyvaluestrings LIKE '%www.website.us%' THEN 'USA'
WHEN propertyvaluestrings LIKE '%www.website.com.br%' THEN 'Brazil'
WHEN propertyvaluestrings LIKE '%www.website.co.id%' THEN 'indonesia'
WHEN propertyvaluestrings LIKE '%www.website.com%' THEN 'Global'
ELSE 'XXXXXXXXXXXXXXXX----Unknown'
END) AS [Site]
,
propertyvaluestrings
FROM Profiles
) X
GROUP BY Site