我需要在OS X上获得目标C / C的总CPU空闲时间吗?
如果可能,请提供代码示例。 这是我用来获取这些指标的代码。结果百分比与我在Activity Monitor中的百分比不同。所以我假设CPU时间计算不正确:
#include <sys/sysctl.h>
#include <sys/types.h>
#include <mach/mach.h>
#include <mach/processor_info.h>
#include <mach/mach_host.h>
- (void)printCPUUsage
{
processor_cpu_load_info_t cpuLoad;
mach_msg_type_number_t processorMsgCount;
natural_t processorCount;
uint64_t totalSystemTime = 0, totalUserTime = 0, totalIdleTime = 0, totalCPUTime = 0;
kern_return_t err = host_processor_info(mach_host_self(), PROCESSOR_CPU_LOAD_INFO, &processorCount, (processor_info_array_t *)&cpuLoad, &processorMsgCount);
for (natural_t i = 0; i < processorCount; i++) {
// Calc load types and totals, with guards against 32-bit overflow
// (values are natural_t)
uint64_t system = 0, user = 0, idle = 0, total = 0;
system = cpuLoad[i].cpu_ticks[CPU_STATE_SYSTEM];
user = cpuLoad[i].cpu_ticks[CPU_STATE_USER];
idle = cpuLoad[i].cpu_ticks[CPU_STATE_IDLE];
total = system + user + idle;
if (total < 1) {
total = 1;
}
totalCPUTime += total;
totalSystemTime += system;
totalUserTime += user;
totalIdleTime += idle;
}
double onePercent = totalCPUTime/100.0f;
NSLog(@"system: %f", (double)totalSystemTime/(double)onePercent);
NSLog(@"user: %f", (double)totalUserTime/(double)onePercent);
NSLog(@"idle: %f", (double)totalIdleTime/(double)onePercent);
}
答案 0 :(得分:9)
默认情况下,从过程仪表或顶部返回的值是基于样本增量,即它们计算自上一个样本以来的CPU使用率,而不是绝对值。
在模式中调用时,这对应于选项-c n
:
top -c n -l 0 | head -5
这是默认模式。如果您想要在代码中返回的值,那么您需要使用以下方法将值基于立即样本:
top -c e -l 0 | head -5
这些值将与您看到的值相对应。
如果要获得与过程仪表/顶部相似的值,则需要采样两个样本,并显示它们之间差异的值。
例如,我们创建一个包含统计信息的结构:
struct cpusample {
uint64_t totalSystemTime;
uint64_t totalUserTime;
uint64_t totalIdleTime;
};
我们改变了printCPUUsage调用,以便它执行一个示例:
void sample(struct cpusample *sample)
{
processor_cpu_load_info_t cpuLoad;
mach_msg_type_number_t processorMsgCount;
natural_t processorCount;
uint64_t totalSystemTime = 0, totalUserTime = 0, totalIdleTime = 0;
kern_return_t err = host_processor_info(mach_host_self(), PROCESSOR_CPU_LOAD_INFO, &processorCount, (processor_info_array_t *)&cpuLoad, &processorMsgCount);
for (natural_t i = 0; i < processorCount; i++) {
// Calc load types and totals, with guards against 32-bit overflow
// (values are natural_t)
uint64_t system = 0, user = 0, idle = 0;
system = cpuLoad[i].cpu_ticks[CPU_STATE_SYSTEM];
user = cpuLoad[i].cpu_ticks[CPU_STATE_USER] + cpuLoad[i].cpu_ticks[CPU_STATE_NICE];
idle = cpuLoad[i].cpu_ticks[CPU_STATE_IDLE];
totalSystemTime += system;
totalUserTime += user;
totalIdleTime += idle;
}
sample->totalSystemTime = totalSystemTime;
sample->totalUserTime = totalUserTime;
sample->totalIdleTime = totalIdleTime;
}
然后我们采取两个样本(样本之间1秒):
struct cpusample delta;
sample(&sample1);
sleep(1);
sample(&sample2);
deltasample.totalSystemTime = sample2.totalSystemTime - sample1.totalSystemTime;
deltasample.totalUserTime = sample2.totalUserTime - sample1.totalUserTime;
deltasample.totalIdleTime = sample2.totalIdleTime - sample1.totalIdleTime;
添加打印样本代码:
void printSample(struct cpusample *sample)
{
uint64_t total = sample->totalSystemTime + sample->totalUserTime + sample->totalIdleTime;
double onePercent = total/100.0f;
NSLog(@"system: %f", (double)sample->totalSystemTime/(double)onePercent);
NSLog(@"user: %f", (double)sample->totalUserTime/(double)onePercent);
NSLog(@"idle: %f", (double)sample->totalIdleTime/(double)onePercent);
}
因此,当您调用printSample(&deltasample)
时,它会打印增量记录,该记录的值与top
或Activity Monitor
提供的值相似。
但说实话,我会使用host_statistics
,因为代码更清晰:
void sample(struct cpusample *sample)
{
kern_return_t kr;
mach_msg_type_number_t count;
host_cpu_load_info_data_t r_load;
uint64_t totalSystemTime = 0, totalUserTime = 0, totalIdleTime = 0;
count = HOST_CPU_LOAD_INFO_COUNT;
kr = host_statistics(mach_host_self(), HOST_CPU_LOAD_INFO, (int *)&r_load, &count);
if (kr != KERN_SUCCESS) {
printf("oops: %s\n", mach_error_string(kr));
return;
}
sample->totalSystemTime = r_load.cpu_ticks[CPU_STATE_SYSTEM];
sample->totalUserTime = r_load.cpu_ticks[CPU_STATE_USER] + r_load.cpu_ticks[CPU_STATE_NICE];
sample->totalIdleTime = r_load.cpu_ticks[CPU_STATE_IDLE];
}