Question

以下是在localhost服务器中向MySQl数据库发送数据的java代码。该使用的脚本语言是php。 Php代码工作正常，当我输入值时通过浏览器使用它。我觉得沟通有误。但我无法做到调试它。请帮忙。

    package com.example.databasetest1;

    import java.io.IOException;
    import java.util.ArrayList;
    import java.util.List;

    import org.apache.http.NameValuePair;
    import org.apache.http.client.ClientProtocolException;
    import org.apache.http.client.HttpClient;
    import org.apache.http.client.entity.UrlEncodedFormEntity;
    import org.apache.http.client.methods.HttpPost;
    import org.apache.http.impl.client.DefaultHttpClient;
    import org.apache.http.message.BasicNameValuePair;

    import android.os.Bundle;
    import android.app.Activity;
    import android.view.Menu;
    import android.view.View;
    import android.widget.Button;
    import android.widget.EditText;

    public class MainActivity extends Activity {
    Button Enter;
    EditText tName;
    String sName;
        @Override
        protected void onCreate(Bundle savedInstanceState) {
            super.onCreate(savedInstanceState);
            setContentView(R.layout.activity_main);

            Enter = (Button) findViewById(R.id.bEnter);
            tName =(EditText)findViewById(R.id.etName);
            sName=tName.getText().toString();
            Enter.setOnClickListener(new View.OnClickListener() {


                @Override
                public void onClick(View v) {
                    // TODO Auto-generated method stub
                    try {
                        HttpClient httpClient = new         DefaultHttpClient();
                        List<NameValuePair> nameValuePair=new ArrayList<NameValuePair>(1);
                        nameValuePair.add(new BasicNameValuePair("Name",sName));
                        HttpPost httpPost = new HttpPost("http://192.168.173.1/try_database/name_insert.php");
                        httpPost.setEntity(new UrlEncodedFormEntity(nameValuePair));
                        httpClient.execute(httpPost);
            } catch (ClientProtocolException e1) {
                        // TODO Auto-generated catch block
                        e1.printStackTrace();
            } catch (IOException e2) {
                // TODO Auto-generated catch block
                e2.printStackTrace();
            }
        }
    });

        }
        /*public void insert() throws ClientProtocolException, IOException
        {
            HttpClient httpClient = new DefaultHttpClient();
            List<NameValuePair> nameValuePair=new ArrayList<NameValuePair>(1);
            nameValuePair.add(new BasicNameValuePair("Name",sName));
            HttpPost httpPost = new HttpPost("http://192.168.173.1/try_database/name_insert.php");
            httpPost.setEntity(new UrlEncodedFormEntity(nameValuePair));
            httpClient.execute(httpPost);
}*/

        @Override
        public boolean onCreateOptionsMenu(Menu menu) {
            // Inflate the menu; this adds items to the action bar if it is present.
            getMenuInflater().inflate(R.menu.main, menu);
            return true;
        }

    }

Answer 1

查看this上的developer.android.com教程。清楚地解释了如何使用类AsyncTask执行与网络相关的操作。

你也可以看看：

http://www.vogella.com/articles/AndroidBackgroundProcessing/article.html

http://examples.javacodegeeks.com/android/core/os/asynctask/android-asynctask-example/

看看这个：

When, why and how to use async task ?

Answer 2

您正在UI线程上执行不允许的n / w i / o。在单独的线程中执行。

Answer 3

您正在Network执行UIThread次处理，这会在后姜饼设备中为您提供例外NetworkOnMainThreadException。您需要将onClick代码移至AsyncTask

无法在数据库中传递值

3 个答案: