从ASP.NET中的Gridview获取当前行

时间:2010-01-12 05:51:37

标签: asp.net gridview edit

我有一个Gridview,删除和编辑按钮看起来像

<asp:GridView ID="grdTrackedItems" runat="server" AutoGenerateColumns="False" Width="330px"
            BorderStyle="None" OnRowDataBound="OnRowDataBoundTrackedItems" OnRowDeleting="OnRowDeletingTrackedItems">
            <Columns>
              <asp:TemplateField HeaderText="Name">
                <ItemTemplate>
                  <asp:Label ID="lblItem" runat="server" Text='<%# Eval("Item") %>' />
                </ItemTemplate>
              </asp:TemplateField>
              <asp:TemplateField>
                <ItemTemplate>
                  <asp:ImageButton ID="imgDelete" runat="server" ImageUrl="~/Resources/Images/Delete.png"
                    Height="12" Width="12" ToolTip="Delete" CommandName="Delete" />
                </ItemTemplate>
                <ItemStyle Width="22px" />
              </asp:TemplateField>
              <asp:TemplateField>
                <ItemTemplate>
                  <asp:ImageButton ID="imgEdit" runat="server" ImageUrl="~/Resources/Images/Edit.png"
                    Height="12" Width="12" ToolTip="Edit" />
                </ItemTemplate>
                <ItemStyle Width="22px" />
              </asp:TemplateField>
            </Columns>
          </asp:GridView>

我在页面底部有一个文本框和“保存”按钮。我想在gridview中单击编辑按钮时在文本框中显示项目名称。我怎么能这样做?

3 个答案:

答案 0 :(得分:3)

在编辑按钮单击处理程序中,您可以访问当前行,如下所示:

protected void Button1_Click1(object sender, EventArgs e)
{
    GridViewRow row = ((ImageButton)sender).Parent.Parent as GridViewRow;
    // Do some thing with this row
}

答案 1 :(得分:3)

为RowEditing事件提供处理程序,然后在该处理程序中更新文本框。

<asp:GridView ID="grdTrackedItems" runat="server" 
             AutoGenerateColumns="False" Width="330px"
            ...
             OnRowEditing="EditRecord">
            <Columns>


protected void EditRecord(object sender, GridViewEditEventArgs e)
{
    Label lbl = (Label)grdTrackedItems.Rows[e.NewEditIndex].Cells[0].FindControl("lblItem");


    MyTextBox.Text = lbl.text;
}

答案 2 :(得分:2)

我从river-blue's回答了解决方案。

将DataKeyNames =“Item”添加到Gridview  并在编辑按钮内单击处理程序

     protected void OnClickEdit( object sender, EventArgs e )
    {
        GridViewRow row = ( (ImageButton) sender ).Parent.Parent as GridViewRow;
        txtName.Text =  grdTrackedItems.DataKeys[row.RowIndex].Value.ToString();
    }