Question

当我尝试使用我的Spring模板基础测试方法调用以下MultipartFile Spring REST URL时，我遇到了以下异常。我怎样才能做到这一点。谢谢。

Spring REST网址：

 @RequestMapping(value = "/media/uploadMultipartFile/{token}/{title}/{trailId}/{wpId}", method = RequestMethod.POST)
 public @ResponseBody MediaHttp uploadMultipartFile(@RequestParam MultipartFile file,
                                                    @PathVariable String token,
                                                    @PathVariable String title,
                                                    @PathVariable String trailId,
                                                    @PathVariable String wpId,
                                                    HttpServletResponse response)

测试方法：

try {

        // Message Converters
        List<HttpMessageConverter<?>> messageConverters = new ArrayList<HttpMessageConverter<?>>();
        messageConverters.add(new FormHttpMessageConverter());
        messageConverters.add(new SourceHttpMessageConverter<Source>());
        messageConverters.add(new StringHttpMessageConverter());
        messageConverters.add(new MappingJacksonHttpMessageConverter());

        // RestTemplate
        RestTemplate template = new RestTemplate();
        template.setMessageConverters(messageConverters);

        // URL Parameters
        MultiValueMap<String, Object> parts = new LinkedMultiValueMap<String, Object>();
        parts.add("token", "nkc2jvbrbc");
        parts.add("title", "test mp4 file");
        parts.add("trailId", "2");
        parts.add("wpId", "7");
        parts.add("file", new FileSystemResource("C:\\Users\\Public\\Pictures\\Sample Pictures\\test.mp4"));

        // Post
        MediaHttp result = template.postForObject(Constants.APPLICATION_URL + "/media/uploadMultipartFile/{token}/{title}/{trailId}/{wpId}", parts, MediaHttp.class);

    } catch (Exception e) {
        System.out.println("Error: " + e.getMessage());
    }

例外：

[http://test.com:8080/DMW-skeleton-1.0/media/uploadMultipartFile/ {token} / {title} / {trailId} / {wpId}]中的变量值无效：预期为4;得到0

Answer 1

消息非常清楚，您没有为提交指定任何路径参数。您只提供将作为请求正文发送的地图。

更改您的调用以包含这些参数作为方法调用的最后一部分。

// URL Parameters
MultiValueMap<String, Object> parts = new LinkedMultiValueMap<String, Object>();
parts.add("file", new FileSystemResource("C:\\Users\\Public\\Pictures\\Sample Pictures\\test.mp4"));
// Post
MediaHttp result = template.postForObject(Constants.APPLICATION_URL + "/media/uploadMultipartFile/{token}/{title}/{trailId}/{wpId}", parts, MediaHttp.class, "nkc2jvbrbc", "test mp4 file", "2", "7);

如何使用RestTemplate调用MultipartFile Spring REST URL

1 个答案: