如何将所有行转换为具有特定列的列作为sqlserver中的头

Question

我想将表的每一行转换为不同的列，使一个特定的行作为转置表的标题。请尽快帮助我。任何简单的例子都可以。

Answer 1

使用PIVOT：

select 
    --userID, Stage1, Stage2, Stage3, Stage4
    *
from (
    select '1' as UserID,'1' as Stage,'1-1-2013' as [Date] union all
    select '1','2','2-1-2013' union all
    select '2','1','1-1-2013' union all
    select '1','3','5-1-2013' union all
    select '2','2','3-1-2013' union all
    select '3','1','6-1-2013' union all
    select '3','2','8-1-2013' union all
    select '1','4','10-1-2013' union all
    select '3','3','12-1-2013'
) x
pivot (
    max([Date]) for Stage in ([1],[2],[3],[4],[5],[6])
) p

有关此主题的更多信息： http://blog.sqlauthority.com/2008/06/07/sql-server-pivot-and-unpivot-table-examples/