我正在做一个phonegap项目,这里我将多个图像上传到服务器,如下图所示,我获得了success
状态以进行图片上传,但是当我在后端检查时,它只显示一个上传的图像(第二个)。请检查上传代码是否有任何错误,并帮助我。
var options = new FileUploadOptions();
options.fileKey="uploadfile";
options.fileName=randomNumber.toString().concat(fileNameSelected);
options.mimeType="image/jpeg";
options.chunkedMode = false;
var ft = new FileTransfer();
// first upload
ft.upload(i1,'http://xx.xx.xx/mobapp/api/upload-image',
function (r){
console.log("ft.upload one"+JSON.stringify(r));
// second upload
ft.upload(i2,'http:/xxx.xx.xx/mobapp/api/upload-image',
function(r){console.log("ft.upload two"+JSON.stringify(r));},
function(error){alert("image upload two failed");},options);
},function(error)
{alert("image upload failed");},options);
感谢。
答案 0 :(得分:0)
1)检查此帖子,在图片标签上添加多个图片
Upload multiple images to the api - phonegap
2)在提交按钮上获取图像src
在你的提交按钮上添加
if($('#vImage1').attr('src')){
/* Image Upload1 Start */
imagefile = $('#vImage1').attr('src');
uploadPhoto(imagefile, "vImage1");
/* Image Upload End */
}
if($('#vImage2').attr('src')){
/* Image Upload2 Start */
imagefile = $('#vImage2').attr('src');
uploadPhoto(imageURI, "vImage2");
/* Image Upload End */
}
function uploadPhoto(imageURI, vImage) {
var imagefile = imageURI;
/* Image Upload Start */
var ft = new FileTransfer();
var options = new FileUploadOptions();
options.fileKey= vImage;
options.fileName=imagefile.substr(imagefile.lastIndexOf('/')+1);
options.mimeType="image/jpeg";
var params = new Object();
params.value1 = "test";
params.value2 = "param";
options.params = params;
options.chunkedMode = false;
ft.upload(imagefile, your_service_url, win, fail, options);
}
使用Cordova处理多个同步上传