Question

我是IOS和RestKit的新手，无法弄清楚如何执行以下操作：

1. a simple POST to a webservice 
  A) with an object payload
  B) Have RestKit Auto Serialize the obj c object into Json

2. Receive the Response
  A) Parse response and extract only certain fields and load into obj c object

我的设置如下：

来自webservice的Json回复：

{
    "user": {
          "id":0,
          "email":"String",
     },
     "errorCode": 0
}

来自Web服务的响应对象，对象：

@interface CreateAccountResponse : NSObject

@property (nonatomic, copy) NSString *id;
@property (nonatomic, copy) NSString *email;
@property (nonatomic) NSInteger   *errorCode;

@end

obj C中的请求对象：

@interface CreateAccountRequestModel : NSObject

@property (nonatomic, copy) NSString *email;
@property (nonatomic, copy) NSString *password;
@property (nonatomic, copy) NSString *first_name;
@property (nonatomic, copy) NSString *last_name;

@end

Webservice希望在POST请求中使用这个Json：

{
    "email":"String",
    "password":"String",
    "first_name":"String",
    "last_name":"String"
}

网址为：www.hostname.com/api/AccountManager/createAccount，它只接受POST请求。

我尝试过：

-(void)SendCreateAccountRequest:(CreateAccountRequestModel*)createActModel
{
    NSString *createAccountUrl = @"www.hostname.com/api/AccountManager/createAccount";
    NSLog(@"SendCreateAccountRequest");
    RKObjectMapping* articleMapping = [RKObjectMapping mappingForClass:  [CreateAccountResponse class]];
    [articleMapping addAttributeMappingsFromDictionary:@{
                                                         @"id": @"user.id",
                                                         @"email": @"user.email",
                                                         @"errorCode": @"errorCode"
                                                         }];

    RKResponseDescriptor *responseDescriptor = [RKResponseDescriptor responseDescriptorWithMapping:articleMapping method:RKRequestMethodAny pathPattern:nil keyPath:@"createAccount" statusCodes:RKStatusCodeIndexSetForClass(RKStatusCodeClassSuccessful)];

    NSURL *URL = [NSURL URLWithString:createAccountUrl];
    NSURLRequest *request = [NSURLRequest requestWithURL:URL];
    RKObjectRequestOperation *objectRequestOperation = [[RKObjectRequestOperation alloc] initWithRequest:request responseDescriptors:@[ responseDescriptor ]];

    [objectRequestOperation setCompletionBlockWithSuccess:^(RKObjectRequestOperation *operation, RKMappingResult *mappingResult)
    {
        RKLogInfo(@"Successful Response: %@", mappingResult.array);
    }
    failure:^(RKObjectRequestOperation *operation, NSError *error)
    {
        RKLogError(@"Operation failed with error: %@", error);
    }];

    [objectRequestOperation start];

我知道我没有正确地将响应从webservice映射到对象，而我没有正确创建POST请求。就像我说我是新人一样，所以你提供的细节越多越好：）

Answer 1

这应该发布一个帖子而不需要第三方库。一旦你开始工作，你可以将getter放在同一个类中并将其称为RestKit，或者使用工作示例来调试RestKit问题。（我的偏好是前者）。

+ (void)postTo:(NSString *)urlString params:(NSDictionary *)params completion:(void (^)(id, NSError *))completion {

    NSURL *url = [NSURL URLWithString:urlString];
    NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url];
    [request setHTTPMethod:@"POST"];

    if (params.count) {
        NSMutableArray *paramArray = [NSMutableArray array];
        for (NSString *key in [params allKeys]) {
            NSString *encodedKey = [key stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
            NSString *encodedValue = [params[key] stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
            NSString *encodedPair = [[encodedKey stringByAppendingString:@"="] stringByAppendingString:encodedValue];
            [paramArray addObject:encodedPair];
        }

        NSString *paramString = [paramArray componentsJoinedByString:@"&"];

        NSData *data = [paramString dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES];
        [request setHTTPBody:data];
        [request setValue:[NSString stringWithFormat:@"%d", [data length]] forHTTPHeaderField:@"Content-Length"];
        [request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"];
    }

    [NSURLConnection sendAsynchronousRequest:request queue:[NSOperationQueue mainQueue] completionHandler:^(NSURLResponse *response, NSData *data, NSError *error) {

        NSHTTPURLResponse *httpResponse = (NSHTTPURLResponse *)response;

        if (!error && httpResponse.statusCode < 400) {
            NSError *parseError;
            id parse = [NSJSONSerialization JSONObjectWithData:data options:NSJSONReadingMutableContainers error:&parseError];
            if (!parseError) {
                completion(parse, nil);
            } else {
                NSLog(@"parse error %@", parseError);
                completion(nil, parseError);
            }
        } else {
            NSLog(@"http status %d, error %@", httpResponse.statusCode, error);
            completion(nil, error);
        }
    }];
}

这样称呼：

NSString *urlString = @"http://www.hostname.com/api/AccountManager/createAccount";
NSDictionary *params = @{ @"email": @"user.email@gmail.com" /* and so on */ };

// assume the method above is a class method in "ThePostingClass"
[ThePostingClass postTo:urlString params:params completion:^(id result, NSError *error) {
    if (!error) {
        NSLog(@"%@", result);
    } else {
        NSLog(@"%@", error);
    }
}];

Getter更容易，将setHttpMethod更改为@“GET”，并可选择通过将paramString作为查询字符串附加来移动params。

Answer 2

您的响应描述符上的

keyPath:@"createAccount"似乎是错误的，因为您的JSON不包含此密钥（因此它应该是keyPath:nil）。实际上应该将其设置为路径模式（pathPattern:@"createAccount"）。

您应该使用RKObjectManager的实例来创建和发送请求 - 这样您就可以轻松地序列化要发送的请求对象。要启用此功能，您需要创建一个请求描述符，其中包含对象中键的映射（名称不会更改，因此它是一个简单的映射）。

使用RKObjectManager时，用它注册请求和响应描述符，然后只注册GET / POST对象。 RKObjectManager将根据您在请求中指定的路径确定应使用哪些请求和响应映射。

创建RKObjectManager时，请使用www.hostname.com/api/AccountManager的基本网址。

最后，要发送JSON，您需要在requestSerializationMIMEType上设置RKObjectManager（因为它不默认为JSON）。

Answer 3

用户对象

@interface User : NSObject

@property (nonatomic, copy) NSString *id;
@property (nonatomic, copy) NSString *email;
@property (nonatomic, copy) NSString *password;
@property (nonatomic, copy) NSString *first_name;
@property (nonatomic, copy) NSString *last_name;

@end

POST http://www.hostname.com/api/AccountManager/createAccount

回应JSON

{
    "id":0,
    "email":"String",
}

在服务器上创建

- (void)createUserOnServer:(User *)user
{
    RKObjectMapping *responseMapping = [RKObjectMapping mappingForClass:[User class]];
    [responseMapping addAttributeMappingsFromArray:@[@"id",@"email"]];
    NSIndexSet *statusCodes = RKStatusCodeIndexSetForClass(RKStatusCodeClassSuccessful);
    RKResponseDescriptor *userResponseDescriptor = [RKResponseDescriptor responseDescriptorWithMapping:responseMapping method:RKRequestMethodAny pathPattern:@"/createAccount" keyPath:@"article" statusCodes:statusCodes];

    RKObjectMapping *requestMapping = [RKObjectMapping requestMapping]; // objectClass == NSMutableDictionary
    [requestMapping addAttributeMappingsFromArray:@[@"email", @"password", @"first_name", @"last_name"]];

    RKRequestDescriptor *requestDescriptor = [RKRequestDescriptor requestDescriptorWithMapping:requestMapping objectClass:[Article class] rootKeyPath:nil method:RKRequestMethodAny];

    RKObjectManager *manager = [RKObjectManager managerWithBaseURL:[NSURL URLWithString:@"http://www.hostname.com/api/AccountManager"];
    [manager addRequestDescriptor:requestDescriptor];
    [manager addResponseDescriptor:articleDescriptor];
    [manager postObject:user path:@"/createAccount" parameters:nil success:^(RKObjectRequestOperation *operation, RKMappingResult *mappingResult) {
                NSLog(@"Create User Success");
            } failure:^(RKObjectRequestOperation *operation, NSError *error) {
                NSLog(@"Create User Error: %@", error);
            }];
}

PS：你最好完全阅读Restkit的README !!

PS2：HTTP statusCode的错误代码更好

RestKit用对象做一个帖子并获得对象响应

3 个答案: