Question

我使用aspjson（json2.asp）来解析来自factual.com的数据，但我遇到了一些问题。

json数据的结构如下：

{
"version":3,
"status":"ok",
"response":{
"data":[
    {
        "address":"12725 SW Pacific Hwy",
        "alcohol":true,
        "attire":"casual",
        "category_ids":[358],
        "category_labels":[["Social","Food and Dining","Restaurants","Italian"]],
        "country":"us","cuisine":["Italian","Pizza","Deli","European","Cafe"],
        "factual_id":"22f39245-7435-4e64-b288-9d84f6f20df9",
        "groups_goodfor":true,
        "kids_goodfor":true,
        "latitude":45.42775,
        "locality":"Portland",
        "longitude":-122.77711,
        "meal_breakfast":true,
        "meal_cater":true,
        "meal_deliver":false,
        "meal_dinner":true,
        "meal_lunch":true,
        "meal_takeout":true,
        "name":"New York New York",
        "neighborhood":["Bull Mountain","Tigard","Robinson","SW Portland","Jean","Greton"],
        "parking":true,
        "parking_lot":true,
        "parking_street":true,
        "postcode":"97223",
        "price":2,
        "rating":3,
        "region":"OR",
        "reservations":true,
        "seating_outdoor":true,
        "status":"1",
        "tel":"(503) 443-2404",
        "website":"http://www.nynytigard.com",
        "wifi":false},

        and many other records.......
        }]
    }

这是我在ASP页面上用来解析数据的脚本：

url_factual="http://api.v3.factual.com/t/restaurants-us?q=%22New%20York%22&KEY=MY_KEY"


set xmlhttp = CreateObject("MSXML2.ServerXMLHTTP") 
   xmlhttp.open "GET", url_factual, false 
  xmlhttp.send ""
Dim oJSON
Set oJSON = New aspJSON
    oJSON.loadJSON(xmlhttp.responseText)
    for each data_object in oJSON.data("response")
        for each elemento In oJSON.data("response").item("data")
response.write(oJSON.data("response").item("data").item("address") & "<br>")
response.write(oJSON.data("response").item("data").item("attire") & "<br>")
    response.write("----------------------------------------------------<br>")
    next
        next


'Response.Write oJSON.JSONoutput()
Set oJSON = Nothing
set xmlhttp = nothing

问题在于我没有价值观。代码中有什么问题？谢谢你的宝贵帮助。

json2.asp数据解析不起作用

0 个答案: