Question

这是交易：我需要填写一个工作日日期（Mo-fr）的数组，从现在开始直到下周末。例如：

今天的日期：12月13日星期三

输出：

workdayArray{
   [0] => 2013/12/13 00:00:00   (Wed)
   [1] => 2013/12/14 00:00:00   (Thur)
   [2] => 2013/12/15 00:00:00   (Fri)
   [3] => 2013/12/18 00:00:00   (Mo)
   [4] => 2013/12/19 00:00:00   (Tue)
   [5] => 2013/12/20 00:00:00   (Wed)
   [6] => 2013/12/21 00:00:00   (Thur)
   [7] => 2013/12/22 00:00:00   (Fri)
}

以下是我的尝试：

//Our array we want to populate     
NSMutableArray *ScheduleDays = [[NSMutableArray alloc] init];

//Setting timezone
NSDateFormatter *dt = [[NSDateFormatter alloc] init];
[dt setTimeZone:[NSTimeZone timeZoneWithAbbreviation:@"GMT"]];

//Setting today's date and weekday        
NSDate *today = [NSDate date];
NSCalendar *gregorian = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
gregorian.firstWeekday = 2;
NSDateComponents *comps = [gregorian components:NSWeekdayCalendarUnit fromDate:today];
int weekday = [comps weekday];

//hardcoding iterations needed to fetch all dates       
int counter=7;
switch(weekday){
    case 1: counter=13; break;
    case 2: counter=12; break;
    case 3: counter=11; break;
    case 4: counter=10; break;
    case 5: counter=9; break;
    case 6: counter=8; break;
    case 7: counter=14; break;
}

//Populating ScheduleDays while skipping Saturday and Sunday
NSDate *date = today;
for(int x=0;x<counter;x++){
    NSCalendar *gregorian = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
    NSDateComponents *formatWeekday = [gregorian components:NSWeekdayCalendarUnit fromDate:date];
    int weekday = [formatWeekday weekday];
    if (weekday!=1 & weekday!= 7) {
        [ScheduleDays addObject:date];
    }
    date = [date dateByAddingTimeInterval:60*60*24*1];
}

“它有效，有什么问题？” 当需要硬编码迭代和跳过工作日时，它似乎是一个非常草率的代码（我认为）。我试图找出如何设计一种有效的方法，而不是基于工作日的硬编码迭代等。对这个设计问题的任何帮助或想法都会很棒。

当前和下周的工作日日期列表

0 个答案: