Question

我需要Listbox1的选定项目来为第二个Listbox提供XmlDataprovider源。

Listbox1使用：

<XmlDataProvider x:Key="CategoryXML"
                 Source="C:\Category.xml"
                 XPath="category"
                 />

Ex：Category.xml

<?xml version="1.0" encoding="ISO-8859-1"?>

<main>
<category>
    <name>Local</name>
    <XmlFileName>C:\Doc1.xml</XmlFileName>
</category>
<category>
    <name>National</name>
    <XmlFileName>C:\Doc2.xml</XmlFileName>
</category>
<category>
    <name>Global</name>
    <XmlFileName>C:\Doc3.xml</XmlFileName>
</category>
</main>

XAML：

<ListBox ItemsSource="{Binding Source={StaticResource CategoryXML},XPath=//main//category}"
         SynchronizedWithCurrentItem="True" Name="CategoryList">

ListBox2：

<XmlDataProvider x:Key="itemXML"
                 Source="?" **XmlFileName of select item in Listbox1**
                 XPath="item"
                 />

我遇到的问题是找到使XmlFileName成为itemXML源的正确语法。用户将在ListBox1中选择<name>并将<XmlFileName>发送到为Feedbox2提供的itemXML

Answer 1

我不知道你可以通过普通的数据绑定来做到这一点。但是有一点代码隐藏很容易：

<Window x:Class="WpfApplication11.Window1"
    xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
    xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
    Title="Window1" Height="300" Width="300">
    <Window.Resources>
        <XmlDataProvider x:Key="Master" Source="Master.xml" XPath="Master/Item"/>
        <XmlDataProvider x:Key="Detail" XPath="Detail/Item"/>
    </Window.Resources>
    <StackPanel>
        <ListBox 
            Name="MasterList"
            ItemsSource="{Binding Source={StaticResource Master}}"
            SelectionChanged="MasterList_SelectionChanged">
            <ListBox.ItemTemplate>
                <DataTemplate>
                    <TextBox Text="{Binding XPath=Description}"/>
                </DataTemplate>
            </ListBox.ItemTemplate>
        </ListBox>
        <ListBox Name="DetailList" ItemsSource="{Binding Source={StaticResource Detail}}">
            <ListBox.ItemTemplate>
                <DataTemplate>
                    <TextBlock Text="{Binding XPath=Description, Mode=TwoWay}"/>
                </DataTemplate>
            </ListBox.ItemTemplate>
        </ListBox>
    </StackPanel>
</Window>

然后：

private void MasterList_SelectionChanged(object sender, SelectionChangedEventArgs e)
{
    ListBox lb = sender as ListBox;
    XmlElement elm = lb.SelectedItem as XmlElement;
    string filename = elm.SelectSingleNode("Filename").InnerText;
    XmlDocument d = new XmlDocument();
    d.Load(filename);
    XmlDataProvider p = Resources["Detail"] as XmlDataProvider;
    p.Document = d;
}

这是有效的，因为每当您设置XmlDataProvider属性时Document都会刷新。您也可以从文件名构造一个URI并设置Source属性;也刷新它。

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