有一个AppViewModel,其中通过调用ActivateItem激活其他ViewModel。
示例正在为我工作:我可以看到相应的视图。
我现在想要从另一个ViewModel激活ViewModel。它被实例化,但不显示相应的视图。
如何激活" GreenScreenViewModel"来自" RedScreenViewModel"?
APPVIEW:
<UserControl x:Class="CaliburnMicroApp_Navigation.AppView"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006">
<DockPanel Background="LightBlue" MinHeight="400" MinWidth="400">
<StackPanel Orientation="Horizontal" DockPanel.Dock="Top" HorizontalAlignment="Center">
<Button x:Name="ShowRedScreen" Content="Red" Width="50" />
<Button x:Name="ShowGreenScreen" Content="Green" Width="50" Margin="12,0,0,0" />
<Button x:Name="ShowBlueScreen" Content="Blue" Width="50" Margin="12,0,0,0" />
</StackPanel>
<ContentControl x:Name="ActiveItem" />
</DockPanel>
</UserControl>
AppViewModel
public class AppViewModel : Conductor<object>
{
public void ShowRedScreen()
{
ActivateItem(new RedViewModel());
}
public void ShowGreenScreen()
{
ActivateItem(new GreenViewModel());
}
public void ShowBlueScreen()
{
ActivateItem(new BlueViewModel());
}
}
RedViewModel - 这不显示GreenView()
public class RedViewModel : Conductor<object>
{
public void DisplayGreen()
{
ActivateItem(new GrenViewModel());
}
}
RedView
<Grid Background="Red">
<StackPanel>
<TextBlock Text="red" FontSize="48" FontWeight="Bold" Foreground="#3CA527" />
<Button Name="DisplayGreen">
<TextBlock >Next Screen</TextBlock>
</Button>
</StackPanel>
</Grid>
答案 0 :(得分:1)
如果您希望在ActiveItem
中按ContentControl
时AppView
Button
中显示的RedViewModel
更改,则需要使用EventAggregator
将RedViewModel
的消息传递给您的AppViewModel
。