Question

我不明白为什么我的程序中出现了分段错误。有人可以解释这个问题吗？

#include <stdlib.h>
#include <iostream>
#include <vector>
using namespace std;
class HashTable {
private:
    int *A[1];
    int n;
    int bsize;
    vector<int> B;

public:
    HashTable(int size) {
        n = size;
        bsize = 0;
        *A = new int[n];
    }
    /*
    You should use another array B besides A. You do not initialize A, and thus the cells of A contain
    garbage initially. The array B is a std::vector which is initially empty. Use the same hash function
    h(x) = x. If A[x] contains i and B[i] contains x, it means that x exists in the hash table. If A[x]
    contains i but B[i] does not contain x or i is out of the range of B, it means that x does not exist in
    the hash table.
    */
    bool insert_hash(int x) {
        if (x >= n) {//sees if x is within the range of A
        } else {
            if (*A[x] > bsize){//sees if i is within the range of B
            } else {
                if (B[*A[x]] == x) {//sees if B[i] contains x

                    return false;
                }
            }

        }
        B.push_back(x);//adds key x to B
        bsize++;
        *A[x] = bsize;//store location at A
        return true;

    //The new key x should be pushed at the back of B and its location is stored at A[x]. This function
    //should return false if x already exists in the hash table, and returns true otherwise.
    }

    bool member_hash(int x) {
    //The function returns true if x exists in the hash table, and returns false otherwise.
        if (x <= n) {//sees if x is within the range of A
            if (*A[x] > bsize){//sees if i is within the range of B
                if (B[*A[x]] == x) {//sees if B[i] is x
                    return true;
                }
            }
        }
        return false;
    }

    bool delete_hash(int x) {
    //This function First checks whether x exists in the hash table: If no, then it returns false. Otherwise,
    //it stores -1 at the cell of B that contains x and then returns true.
        if (!member_hash(x)) {
            return false;
        } else {
            B[*A[x]] = -1;
            return true;
        }
    }
};

int main() {
    HashTable a(20);
    a.insert_hash(5);
    a.insert_hash(4);
    a.insert_hash(2);
    a.insert_hash(2);
    a.insert_hash(11);
    a.insert_hash(510);
    a.member_hash(11);
    a.delete_hash(11);
    a.member_hash(11);
    return 0;
}

我在DevC ++和Code :: Blocks中编译代码很好，但是当我尝试运行此代码时，它最终没有响应，当我在CodePad上运行它时，我收到消息Segmentation Fault。编辑：更具体地说，它说“分段错误（核心转储）” 编辑2：似乎Segmentation fault开始于main中的第一个insert_hash，条件语句（B [* A [x]] == x）关于如何解决这个问题的任何想法？编辑3：B [* A [x]] == x，从member_hash开始，似乎是因为B为空。但是，我很困惑* A [x]中的垃圾值如何达到这个条件，因为我有其他条件（* A [x]＆lt; bsize）和（x＆lt; n）来防范这种情况。溶液

Answer 1

int *A[1];表示将A声明为指向int的一个元素的数组。

您的数组分配编译但不好，您在未知地址分配int数组（此时A [0]未定义）

如果我正确理解你想要实现的目标，你需要的是A是n个int类型元素的数组。

所以我相应地更新你的代码：

#include <stdlib.h>
#include <iostream>
#include <vector>
using namespace std;
class HashTable {
private:
    int *A;
    int n;
    int bsize;
    vector<int> B;

public:
    HashTable(int size) {
        n = size;
        bsize = 0;
        A = new int[n];
    }
    /*
    You should use another array B besides A. You do not initialize A, and thus the cells of A contain
    garbage initially. The array B is a std::vector which is initially empty. Use the same hash function
    h(x) = x. If A[x] contains i and B[i] contains x, it means that x exists in the hash table. If A[x]
    contains i but B[i] does not contain x or i is out of the range of B, it means that x does not exist in
    the hash table.
    */
    bool insert_hash(int x) {
        if (x >= n) {//sees if x is within the range of A
        } else {
            if (A[x] > bsize){//sees if i is within the range of B
            } else {
                if (B[A[x]] == x) {//sees if B[i] contains x

                    return false;
                }
            }

        }
        B.push_back(x);//adds key x to B
        bsize++;
        A[x] = bsize;//store location at A
        return true;

    //The new key x should be pushed at the back of B and its location is stored at A[x]. This function
    //should return false if x already exists in the hash table, and returns true otherwise.
    }

    bool member_hash(int x) {
    //The function returns true if x exists in the hash table, and returns false otherwise.
        if (x <= n) {//sees if x is within the range of A
            if (A[x] > bsize){//sees if i is within the range of B
                if (B[A[x]] == x) {//sees if B[i] is x
                    return true;
                }
            }
        }
        return false;
    }

    bool delete_hash(int x) {
    //This function First checks whether x exists in the hash table: If no, then it returns false. Otherwise,
    //it stores -1 at the cell of B that contains x and then returns true.
        if (!member_hash(x)) {
            return false;
        } else {
            B[A[x]] = -1;
            return true;
        }
    }
};

int main() {
    HashTable a(20);
    a.insert_hash(5);
    a.insert_hash(4);
    a.insert_hash(2);
    a.insert_hash(2);
    a.insert_hash(11);
    a.insert_hash(510);
    a.member_hash(11);
    a.delete_hash(11);
    a.member_hash(11);
    return 0;
}

哈希表中的分段错误

1 个答案: