Question

此代码有什么问题？

rectangle :: Int -> Int -> String
rectangle i j
    | i < 0 || j < 0    = ""
    | otherwise         = concatenate(i) ++ "n/" ++ (rectangle i) j-1




concatenate :: Int -> String
concatenate i
    | i <= 0            = ""
    | otherwise         = "*" ++ concatenate(i-1)

这是我得到的错误

  ERROR line 3 - Instance of Num [Char] required for definition of rectangle

这应该是它所做的（例如）

Main> putStr (rectangle 3 4)
****
****
****

Answer 1

您迟早会习惯Haskell语法。这是

(rectangle i) j-1

被解析为

(rectangle i j) - 1

但你真的想要：

rectangle i (j-1)

Answer 2

此代码应该有效。

rectangle :: Int -> Int -> String
rectangle i j
    | i < 0 || j < 0    = ""
    | otherwise         = concatenate i ++ "\n" ++ rectangle i (j-1)




concatenate :: Int -> String
concatenate i
    | i <= 0            = ""
    | otherwise         = "*" ++ concatenate (i-1)

很少有评论：

concatenate(i) ==> concatenate i
-- You don't need to put parameters in brackets in haskell.
(rectangle i) j-1 ==> rectangle i (j-1)
-- See Ingo's explanation
"n/" ==> "\n"
-- That should be obvious

Haskell Num问题实例

2 个答案: