Question

我目前正在尝试制作一个涉及随机生成的世界的游戏。我目前有一个工作的启动画面和一个工作的perlin噪音，它正常化。我只需要一种实现代码来显示图像的方法。

代码：

public void show() {
    batch = new SpriteBatch();
    World world = new World();


    int type = 0;

    for (int y = 1; y < world.getlengthy();y++){
        for (int x = 1; x < world.getlengthx();x++){
        type = world.getvalue(x, y);


        switch (type) {
            case 1:sprite = new Sprite(tex1,0,0,16,16);sprite.setPosition(x, y);batch.begin();sprite.draw(batch);batch.end();
            Gdx.app.log("", "x: " + x + " y: " + y);
            break;
            case 2:batch.begin();batch.draw(tex2, x, y);batch.end();
            break;
            case 3:batch.begin();batch.draw(tex3, x, y);batch.end();
            break;
            case 4:batch.begin();batch.draw(tex4, x, y);batch.end();
            break;
            case 5:batch.begin();batch.draw(tex5, x, y);batch.end();
            break;
            case 6:batch.begin();batch.draw(tex6, x, y);batch.end();
            break;
            case 7:batch.begin();batch.draw(tex7, x, y);batch.end();
            break;
            case 8:batch.begin();batch.draw(tex8, x, y);batch.end();
            break;
            }
        }

Answer 1

您的代码必须位于render方法内。如果第一次显示屏幕，则会调用该节目。（1次调用！）所以将for循环置于渲染周期内，它应该可以工作。

就像一个小小的提示。不要在渲染周期sprite = new Sprite(tex1,0,0,16,16);内创建对象。始终初始化show方法中或构造函数内部的所有对象以保存rendertime。（它确实在帧速率上有很大的不同）

循环后只有begin()一次和end()。

例如像这样的东西。我仍然不会在渲染中创建精灵，但我不知道你的其余逻辑。希望这可以帮助！此致

@Override
public void show() {
    batch = new SpriteBatch();
    World world = new World();
}


@Override
public void render(float delta){
    int type = 0;
    batch.begin();
    for (int y = 1; y < world.getlengthy();y++){
        for (int x = 1; x < world.getlengthx();x++){
        type = world.getvalue(x, y);


        switch (type) {
            case 1:
                sprite = new Sprite(tex1,0,0,16,16);
                sprite.setPosition(x, y);
                sprite.draw(batch);
                Gdx.app.log("", "x: " + x + " y: " + y);
            break;
            case 2:
                batch.draw(tex2, x, y);
            break;
            case 3:
                batch.draw(tex3, x, y);
            break;
            case 4:
                batch.draw(tex4, x, y);
            break;
            case 5:
                batch.draw(tex5, x, y);
            break;
            case 6:
                batch.draw(tex6, x, y);
            break;
            case 7:
                batch.draw(tex7, x, y);
            break;
            case 8:
                batch.draw(tex8, x, y);
            break;
            }
        }
        batch.end();
}

如何在嵌套的switch语句中显示图像？

1 个答案: