//**************************************************************************************************************
// FILE: a04.cpp
//**************************************************************************************************************
#include <fstream>
#include <iostream>
#include "Sorter.hpp"
using namespace std;
// Write the function header for Merge ()
void Merge(int a[] , int b[],int c[], int n)
{
int i = 0, j = 0, k = 0;
while (i < n || j < n) {
// Write the if-elseif-elseif-... statement in the body of the while loop
if (i < n && j < n && a<=b) {
c = a;
i++;
}
else if (i < n && j < n && a > b) {
c =b;
j++;
}
else if (i < n) {
c = a;
i++;
}
else {
c =b;
j++;
}
k++;
} // end while
} // end function merge
void ReadList(ifstream fin, int a[], int n);
void ReadFile(int a[], int b[], int& n)
{
ifstream fin ("ints-in.txt");
ReadList(fin,a,n); // come back again different than the psuedo code
ReadList(fin,b,n);
fin.close();
}
// Write the function header for ReadList()
void ReadList(ifstream fin, int a[], int n)
{
n = 0;
int number;
// Implement the sentinel loop
while (fin >> number && number != -1) {
a[n] = number;
n++; // come back again
}
}
void WriteFile(int a[], int n)
{
ofstream fout("ints-out.txt");
// Write a vary loop where variable ivaries from 0 to n - 1. In the loop send a[i] and ' ' to fout.
for (int i =0; i <= n-1; i++) {
fout << a << ' '; // come back again.
}
fout << -1;
fout.close();
}
int main()
{
// Define int arrays a,b, and c and int variable n.
int a[100], b[100], c[200];
int n;
// Call ReadFile () passing a,b, and n
ReadFile(a,b,n);
// Define and create a Sorter object named sorter
Sorter sorter;
// Call SelectionSort() on sorter to sort a into ascending order.
// Hint: to access the ASCENDING constant data member of the Sorter class you write Sorter::ASCENDING.
sorter.SelectionSort(a,100,Sorter::ASCENDING); //come back again here.
// Call BubbleSort () on sorter to sort b into ascending order
sorter.BubbleSort(b,100,Sorter::ASCENDING);
// Call Merge() passing a,b,c, and n
Merge(a,b,c,n);
// Call WriteFile () passing c and 2n
WriteFile(c,2*n);
return 0;
}
我不知道为什么无法编译。
错误1错误C2248: 'std :: basic_ifstream&lt; _Elem,_Traits&gt; :: basic_ifstream':无法访问 私人成员在课堂上宣布 '的std :: basic_ifstream&LT; _Elem,_Traits&GT;' C:\用户\希沙姆\文档\ Visual studio 2012 \ projects \ homework4 \ a04.cpp 39 1 Homework4错误2错误 C2248:'std :: basic_ifstream&lt; _Elem,_Traits&gt; :: basic_ifstream':不能 访问类中声明的私有成员 '的std :: basic_ifstream&LT; _Elem,_Traits&GT;' C:\用户\希沙姆\文档\ Visual studio 2012 \ projects \ homework4 \ a04.cpp 40 1 Homework4 3 IntelliSense: “std :: basic_ifstream&lt; _Elem,_Traits&gt; :: basic_ifstream(const std :: basic_ifstream&lt; _Elem,_Traits&gt; :: _ Myt&amp; _Right)[with _Elem = char, _Traits = std :: char_traits]“(在”C:\ Program Files(x86)\ Microsoft Visual Studio 11.0 \ VC \ include \ fstream“的第827行声明) 无法访问c:\ Users \ Hisham \ Documents \ Visual Studio 2012 \ Projects \ Homework4 \ a04.cpp 39 11家庭作业4 4智能感知: “std :: basic_ifstream&lt; _Elem,_Traits&gt; :: basic_ifstream(const std :: basic_ifstream&lt; _Elem,_Traits&gt; :: _ Myt&amp; _Right)[with _Elem = char, _Traits = std :: char_traits]“(在”C:\ Program Files(x86)\ Microsoft Visual Studio 11.0 \ VC \ include \ fstream“的第827行声明) 无法访问c:\ Users \ Hisham \ Documents \ Visual Studio 2012 \ Projects \ Homework4 \ a04.cpp 40 11 Homework4
感谢。
答案 0 :(得分:5)
该错误并未说明ifstream
无法访问。它(以其自己的复杂方式)说复制构造函数是不可访问的,因为它被声明为私有。问题是你通过值传递ifstream
,它试图调用无法访问的拷贝构造函数。
void ReadList(ifstream fin, int a[], int n)
通过引用传递它。
void ReadList(ifstream & fin, int a[], int n)
答案 1 :(得分:1)
iostream不可复制,因此无法按值传递它们。
答案 2 :(得分:1)
void ReadFile(int a[], int b[], int& n)
{
ifstream fin ("ints-in.txt");
ReadList(fin,a,n); // come back again different than the psuedo code
ReadList(fin,b,n);
fin.close();
}
void ReadList(ifstream fin, int a[], int n)
您正在尝试按副本传递istream实例。你不能那样做 - 复制构造函数被标记为私有。
您需要将ReadList函数声明为:
void ReadList(ifstream& fin, int a[], int n)
答案 3 :(得分:0)
我一直在研究这个相同的代码,我在Merge()函数中有不同的东西。
void Merge(int a[], int b[], int c[], int& n)
{
int i = 0, j = 0, k = 0;
while (i < n || j < n)
{
if (i < n && j < n && a[i] <= b[j])
{c[k] = a[i];
i++;}
else if (i < n && j < n && a[i] > b[j])
{c[k] = b[j];
j++;}
else if (i < n)
{c[k] = a[i];
i++;}
else
{c[k] = b[j];
j++;}
k++;
}
}
我把i,j和k放在括号中。 我不确定这是否正确,但我在这方面没有任何错误消息。