Question

下面的代码从雅虎获取rss提要并且它有效但我有一点问题，当我擦代码时，它返回提要但它也给我一个错误，如 -

未定义的偏移量：第8行/Applications/MAMP/htdocs/feedbackFtms/rss.php中的1

line 8 is - $foundImg = $findImg[1];

<div class="feed">
    <link rel="stylesheet" href="css/profilepage.css">

    <?php
        function getImageFromContext($context){

        $findImg = explode('<img src="',$context);
        $foundImg = $findImg[1];
        $findExt = explode('.jpg',$foundImg);
        $getIMG = $findExt[0].'.jpg';
        return $getIMG;
        }

       function getFeed($url){
        $x = simplexml_load_file($url);
        echo "<ul>";
        foreach($x->channel->item as $entry) {
            echo "<li><img src='".getImageFromContext($entry->description)."' /><a href='{$entry->link}' title='{$entry->title}'>{$entry->title}</a></li><br>";
            }
            echo "</ul>";
        }
        getFeed("http://news.yahoo.com/rss/entertainment");
    ?>
    </div>

Answer 1

试试这个，

 foreach($x->channel->item as $entry) {
        echo "<li><img src='".getImageFromContext('<img src="'.$entry->description)."' /><a href='{$entry->link}' title='{$entry->title}'>{$entry->title}</a></li><br>";
        }
        echo "</ul>";
    }

我不确定在getImageFromContext函数返回之前是否需要最后两行。

Answer 2

有些文章没有图片。

你可以按原样改变你的代码，我想它会起作用但是这样使用正则表达式会更方便。

<?php
function getImageFromContext($context){

    $findImg = explode('<img src="',$context);
    if(isset($findImg[1])){
        $foundImg = $findImg[1];
        $findExt = explode('.jpg',$foundImg);
        $getIMG = '<img src="' . $findExt[0].'.jpg' . '" />';

        return $getIMG;
    }

    return '';
    }

function getFeed($url){
    $x = simplexml_load_file($url);

    echo "<ul>";
    foreach($x->channel->item as $entry) {
        echo "<li>".getImageFromContext($entry->description)."<a href='{$entry->link}' title='{$entry->title}'>{$entry->title}</a></li><br>";
        }
        echo "</ul>";
    }
    getFeed("http://news.yahoo.com/rss/entertainment");

?>

</div>

在我的网站上获取RSS订阅源

2 个答案: