Question

我想要实现的是我想创建一个链接，用于在网页上的某个地方下载文件，用于通过php发送新上传的文件 php代码看起来像这样：
`

    $target_path = "uploads/";      
$filename = $_FILES['userfile']['name'];      
$ext = pathinfo($filename, PATHINFO_EXTENSION);      
$allowed =  array('gp5','gp4' ,'gp3');  
$filename = $_FILES['userfile']['name'];  
$ext = pathinfo($filename, PATHINFO_EXTENSION);  
if(!in_array($ext,$allowed) ) {  
    echo 'not a valid file extension';  
}   
else {  
        $target_path = $target_path . basename( $_FILES['userfile']['name']);  
        if(move_uploaded_file($_FILES['userfile']['tmp_name'], $target_path)) {  
            echo "The file ".  basename( $_FILES['userfile']['name'])." has   been uploaded";  
        } else {  
            echo "There was an error uploading the file, please try again!";  
        }  
}

`

Answer 1

假设目标路径位于web root中的某个位置，您可以在success的{{1}}语句的if部分内执行此操作：

move_uploaded_file

修改

原来你想要的是上传文件的列表：

echo '<a href="'.$target_path.'">'.$file.'</a>';

编辑：从评论中，您希望所有内容都在一个页面中：

将upload.php和example.html合并到example.php中。让表单提交给自己。这样你就不需要去另一页了。

是否可以创建<a href...<="" a=""> for uploaded file with php?</a>

1 个答案: