Question

我的表单包含输入字段，其中包含从mysql表填充的值。在我的select语句中，我将这些值传递给字段。该表名为person，具有唯一标识person_id和外键academy_id。每个人都有一个状态active或inactive存储在字段名称person_status中。我很难从person_status为每个人提取值。如何在选择查询中显示每个人的状态？ EXAMPLE

选择要填充的查询

<?php

   $id = 15; 
$db_select2  = $db_con->prepare("
        SELECT     a.name, 
                   a.academy_id,
                   p.person_id,
                   p.person_status,
                   p.first_name
        FROM academy a
        LEFT JOIN person p ON a.academy_id = p.academy_id
        WHERE a.academy_id = :id
        ");
        if (!$db_select2) return false;
        if (!$db_select2->execute(array(':id' => $id))) return false;
            $results2 = $db_select2->fetchAll(\PDO::FETCH_ASSOC);
            if (empty($results2)) return false;
            $result2 = '';
            $s = 1;
            echo "<table>";
            echo "<tbody>";
        foreach ($results2 as $value2){ 
            echo "<tr>";
            echo "<td>Name #".$s."<input type=\"hidden\" name=\"person_id_".$s."\" value='". $person_id = $value2['person_id']."' readonly=\"readonly\"/><input id=\"person_fname_".$s."\" name=\"person_fname_".$s."\" placeholder=\"Person #".$s." First Name\" type=\"text\" value='" . $value2['first_name'] ."'/></td>";
            echo "</tr>";
                $s++;   
        }
        echo "</tbody>";
        echo "</table>";    


?>

希望将此功能集成到select语句中：

<?php
$table_name2 = "person";
$column_name2 = "person_status";

    echo "<select name=\"$column_name2\"><option>Select one</option>";
    $sql1 = 'SHOW COLUMNS FROM '.$table_name2.' WHERE field="'.$column_name2.'"';
    $row1 = $db_con->query($sql1)->fetch(PDO::FETCH_ASSOC);
    $selected1 = '';
    foreach(explode("','",substr($row1['Type'],6,-2)) as $option) {
    if ($status == $option){
          $selected1 = "selected=selected";
    }else{
          $selected1='';
    }
          echo "<option value='$option'" . $selected1. ">$option</option>";
    }
    echo "</select></br>";   
?>

Answer 1

只获取一次选项（无需为每个人重复此选项）：

$sqlStatuses = 'SHOW COLUMNS FROM '.$table_name2.' WHERE field="'.$column_name2.'"';
$rowStatuses = $db_con->query($sql1)->fetch(PDO::FETCH_ASSOC);
$personStatuses = explode("','",substr($rowStatuses['Type'],6,-2));

然后，走过那些人

foreach ($results2 as $value2) { 
    // Your code
    echo "<tr>";
    echo "<td>Name #".$s."<input type=\"hidden\" name=\"person_id_".$s."\" value='". $person_id = $value2['person_id']."' readonly=\"readonly\"/><input id=\"person_fname_".$s."\" name=\"person_fname_".$s."\" placeholder=\"Person #".$s." First Name\" type=\"text\" value='" . $value2['first_name'] ."'/></td>";

    // Added
    echo '<td><select name="person_status_'.$s.'">';
    foreach($personStatuses as $option) {
        echo '<option value="'.htmlspecialchars($option).'" ';
        if ($value2['person_status'] == $option) {
            echo 'selected="selected"';
        }
        echo '>' . htmlspecialchars($option) . '</option>';
    }
    echo '</select></td>';

    // Your code again
    echo "</tr>";
    $s++;   
}

将此构建为一个SELECT查询是不必要的复杂（尽管可能，但会为您提供不可读的代码）。

哦，看看htmlspecialchars（），如果一个名字包含“-character，你的HTML搞砸了

使用mysql中的值填充选择输入字段

1 个答案: