Question

我正在使用Rinjael在VB.NET中进行编码，需要在Ruby中进行解码。我的VB.NET加密类看起来像这样：

Private Class Encryptor
        Private symmetricKey As System.Security.Cryptography.RijndaelManaged
        Private iVector As Byte()
        Private Key As Byte()
        Public Function encrypt(ByVal data As String) As String
            Try
                Dim plainTextBytes As Byte() = System.Text.Encoding.ASCII.GetBytes(data)
                Dim encryptor As System.Security.Cryptography.ICryptoTransform = symmetricKey.CreateEncryptor(Key, iVector)
                Dim memoryStream As New System.IO.MemoryStream
                Dim cryptoStream As System.Security.Cryptography.CryptoStream = New System.Security.Cryptography.CryptoStream(memoryStream, encryptor, System.Security.Cryptography.CryptoStreamMode.Write)
                cryptoStream.Write(plainTextBytes, 0, plainTextBytes.Length)
                cryptoStream.FlushFinalBlock()
                Dim cipherTextBytes As Byte() = memoryStream.ToArray()
                memoryStream.Close()
                cryptoStream.Close()
                Return Convert.ToBase64String(cipherTextBytes)
            Catch
                Return ""
            End Try
        End Function
        Public Function decrypt(ByVal data As String) As String
            Try
                Dim crypted As Byte() = Convert.FromBase64String(data)
                Dim decryptor As System.Security.Cryptography.ICryptoTransform = symmetricKey.CreateDecryptor(Key, iVector)
                Dim memoryStream As New System.IO.MemoryStream(crypted)
                Dim cryptoStream As System.Security.Cryptography.CryptoStream = New System.Security.Cryptography.CryptoStream(memoryStream, decryptor, System.Security.Cryptography.CryptoStreamMode.Read)
                Dim plain(crypted.Length) As Byte
                Dim count As Integer = cryptoStream.Read(plain, 0, plain.Length)
                memoryStream.Close()
                cryptoStream.Close()
                Return System.Text.Encoding.UTF8.GetString(plain, 0, count)
            Catch
                Return ""
            End Try
        End Function

        Public Sub New(ByVal clientkey As String)
            iVector = System.Text.Encoding.ASCII.GetBytes("1234567890123456")
            Key = System.Text.Encoding.ASCII.GetBytes(clientkey)
            symmetricKey = New System.Security.Cryptography.RijndaelManaged
            symmetricKey.Mode = System.Security.Cryptography.CipherMode.CBC
        End Sub
    End Class

这个工作正常，我可以使用AES / CBC / PKCS5Padding在java中解密。现在，我的密码和iv长16个字符（16 * 16bit = 256）。当我尝试在Ruby中解密时，它抱怨我的密码很短......我认为它使用的是8位字符。我在ruby中使用这个类进行解密：

    require 'openssl'

module Crypt
  # Decrypts a block of data (encrypted_data) given an encryption key
  # and an initialization vector (iv).  Keys, iv's, and the data 
  # returned are all binary strings.  Cipher_type should be
  # "AES-256-CBC", "AES-256-ECB", or any of the cipher types
  # supported by OpenSSL.  Pass nil for the iv if the encryption type
  # doesn't use iv's (like ECB).
  #:return: => String
  #:arg: encrypted_data => String 
  #:arg: key => String
  #:arg: iv => String
  #:arg: cipher_type => String
  def Crypt.decrypt(encrypted_data, key, iv, cipher_type)
    aes = OpenSSL::Cipher::Cipher.new(cipher_type)
    aes.decrypt
    aes.key = key
    aes.iv = iv if iv != nil
    aes.update(encrypted_data) + aes.final  
  end

  # Encrypts a block of data given an encryption key and an 
  # initialization vector (iv).  Keys, iv's, and the data returned 
  # are all binary strings.  Cipher_type should be "AES-256-CBC",
  # "AES-256-ECB", or any of the cipher types supported by OpenSSL.  
  # Pass nil for the iv if the encryption type doesn't use iv's (like
  # ECB).
  #:return: => String
  #:arg: data => String 
  #:arg: key => String
  #:arg: iv => String
  #:arg: cipher_type => String  
  def Crypt.encrypt(data, key, iv, cipher_type)
    aes = OpenSSL::Cipher::Cipher.new(cipher_type)
    aes.encrypt
    aes.key = key
    aes.iv = iv if iv != nil
    aes.update(data) + aes.final      
  end
end

现在。通过尝试使用Crypt.decrypt（数据，密钥，iv，“AES-CBC-256”）进行解密，我确信必须对我的数据，密钥，iv进行初步字符串/字节转换才能正常工作。

如何使用key =“passwordpassword”和iv =“1234567890123456”调用Crypt.decrypt？我需要对我的数据进行base64解码吗？

这是我的解密调用，似乎不起作用（尝试用零填充）：

   text = Base64.decode64(text)
   pass = Digest::SHA1.hexdigest("#{@pass}0000000000000000").unpack('a2'*32).map{|x| x.hex}.pack('c'*32)
   iv = Digest::SHA1.hexdigest("12345678901234560000000000000000").unpack('a2'*32).map{|x| x.hex}.pack('c'*32)
   return Crypt.decrypt(text,pass,iv,"AES-256-CBC")

Answer 1

解。这是一个128位加密（错误地认为.NET托管中的默认值为256）。因此，此代码有效（注意“AES-128-CBC”）：

   text = Base64.decode64(text)
   pass = "passwordpassword"
   iv = "1234567890123456"
   return Crypt.decrypt(text,pass,iv,"AES-128-CBC")

Answer 2

因为VB应用程序将结果编码为base64，所以看起来ruby脚本需要先使用Base64模块对其进行解码。

我认为Ruby AES密钥的密钥必须是256位。因此，在这种情况下，您的密码需要长度为32个字节。最好使用this等方案。

如何在ruby中解码Rijndael（在VB.net中编码）

2 个答案: