Question

我的Google文档电子表格调用以json格式返回此响应（我只需要“行”之后的所有内容）请查看formatted response here：）

我使用php的json_decode函数来解析数据并使用它（是的，我在php上很糟糕）这段代码返回NULL，根据文档，返回NULL “如果json不能被解码“。

$ json = file_get_contents（$ jsonurl）;
  $ json_output = json_decode（$ json）;

var_dump（$ json_output）; //返回NULL

基本上，我想要完成的是从Json响应的第一行值创建一个简单的数组。

像这样

$array = {'john','John Handcock','email@yahoo.com','2929292','blanc'}

你们是天才，我非常感谢你们的见解和帮助！

回答为“sberry2A”提到吼叫，响应无效Json，google为此目的提供了Zend Json library，所以我决定解析tsv-excel版本:)

Answer 1

您提供的链接中的数据不是有效的JSON。您提供的内容似乎是解码版本。你可以告诉它不是JSON，因为没有引用数组键。例如，版本应为“版本”。

您的数据应该更像这样

'{"version":"0.6","reqId":"requestIDnumber","status":"ok","sig":"65724392","table":{"cols":[{"id":"A","label":"slug","type":"string", "pattern":""},{"id":"B","label":"name","type":"string","pattern":""},{"id":"C","label":"email","type":"string","pattern":""},{"id":"D","label" :"nsid","type":"number","pattern":"#0.###############"},{"id":"E","label":"theme","type":"string","pattern":""}],"rows":[{"c":[{"v":"mo"},{"v": "Mohammad Taheri"},{"v":"email@yahoo.com"},{"v":"2929292.0","f":"2929292"},{"v":"blanc"}]}]}}'



$json = '{"version":"0.6","reqId":"requestIDnumber","status":"ok","sig":"65724392","table":{"cols":[{"id":"A","label":"slug","type":"string", "pattern":""},{"id":"B","label":"name","type":"string","pattern":""},{"id":"C","label":"email","type":"string","pattern":""},{"id":"D","label" :"nsid","type":"number","pattern":"#0.###############"},{"id":"E","label":"theme","type":"string","pattern":""}],"rows":[{"c":[{"v":"mo"},{"v": "Mohammad Taheri"},{"v":"email@yahoo.com"},{"v":"2929292.0","f":"2929292"},{"v":"blanc"}]}]}}';
$data = json_decode($json);
print_r($data->table->rows);

//输出

Array ( [0] => stdClass Object ( [c] => Array ( [0] => stdClass Object ( [v] => mo ) [1] => stdClass Object ( [v] => Mohammad Taheri ) [2] => stdClass Object ( [v] => email@yahoo.com ) [3] => stdClass Object ( [v] => 2929292.0 [f] => 2929292 ) [4] => stdClass Object ( [v] => blanc ) ) ) )

Answer 2

您是否尝试从回复myData(...)中删除回调函数？

Answer 3

$json = file_get_contents($jsonfile);
$data = json_decode($json);
print_r($data);

Answer 4

PEAR包Services_Json能够使用不带引号的密钥解析JSON。因此，剥离回调并使用Services_Json进行解析，我相信这将有效。

http://mike.teczno.com/JSON/doc/

如何解码Google电子表格Json响应作为Php阵列

4 个答案: