我想显示数据库中的所有图像。我编写了代码但是显示错误java.sql.SQLException:列索引超出范围,0< 1.下面是我的数据库表
| application_name | varchar(45) |
| application_id | varchar(10) |
| application_path | varchar(500) |
| application_icon | blob |
我想只显示images.below是我的servlet代码
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
// TODO Auto-generated method stub
response.setContentType("image/jpeg");
PrintWriter out=response.getWriter();
try {
Connection connection= DBUtil.getConnection();
PreparedStatement preparedStatement=connection.prepareStatement("select application_icon from application_master");
ResultSet resultSet=preparedStatement.executeQuery();
System.out.println("resultSet"+resultSet);
out.print("<h1>photo</h1>");
while (resultSet.next()) {
out.print("<img width='200' height='200' src="+resultSet.getBlob(0)+ "> </img>" );
}
} catch (ClassNotFoundException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (SQLException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
答案 0 :(得分:16)
列索引应从1开始而不是0
http://docs.oracle.com/javase/7/docs/api/java/sql/ResultSet.html#getBlob(int)
参数:columnIndex - 第一列为1,第二列为2,...
应该是
resultSet.getBlob(1) //first column
答案 1 :(得分:2)
声明应该是这样的
while(resultSet.next())
resultSet.getBlob(1);
col index从1到...
答案 2 :(得分:1)
Blob getBlob(int columnIndex)
throws SQLException
Retrieves the value of the designated column in the current row of this ResultSet object as a Blob object in the Java programming language.
Parameters:
columnIndex - the first column is 1, the second is 2, ...
Returns:
a Blob object representing the SQL BLOB value in the specified column
您尝试按索引0访问列,而枚举以1
开头