我使用远端底部的代码来获取 weblink 和 Masjid名称。但是我想获得面额和街道地址。请帮助我被困住。
目前我收到以下内容
网络链接:
<div class="subtitleLink"><a href="http://www.salatomatic.com/d/Tempe+5313+Masjid-Al-Hijrah">
和清真寺名称
<b>Masjid Al-Hijrah</b>
但是想得到以下内容;
面额
<b>Denomination:</b> Sunni (Traditional)
和街道地址
<br>45 Station Street (Sydney)
以下代码会删除以下内容
<td width=25><a href="http://www.salatomatic.com/d/Tempe+5313+Masjid-Al-Hijrah"><img src='http://www.halalfire.com/images/en/photo_small.jpg' alt='Masjid Al-Hijrah' title='Masjid Al-Hijrah' border=0 width=48 height=36></a></a></td><td width=10><img src="http://www.salatomatic.com/images/spacer.gif" width=10 border=0></td><td nowrap><div class="subtitleLink"><a href="http://www.salatomatic.com/d/Tempe+5313+Masjid-Al-Hijrah"><b>Masjid Al-Hijrah</b></a> </div><div class="tinyLink"><b>Denomination:</b> Sunni (Traditional)<br>45 Station Street (Sydney) </div></td><td align=right valign=center><div class="tinyLink"></div></td>
CODE:
from bs4 import BeautifulSoup
import urllib2
url1 = "http://www.salatomatic.com/c/Sydney+168"
content1 = urllib2.urlopen(url1).read()
soup = BeautifulSoup(content1)
results = soup.findAll("div", {"class" : "subtitleLink"})
for result in results :
br = result.find('b')
a = result.find('a')
currenturl = a.get('href')
if not currenturl.startswith("http"):
currenturl = "http://www.salatomatic.com" + currenturl
print currenturl
elif currenturl.startswith("http"):
print a.get('href')
pos = br.get_text()
print pos
答案 0 :(得分:1)
您可以使用值<div>
的{{1}}属性检查下一个class
元素,该元素包含tinyLink
和<b>
标记并提取其字符串:
<br>