Question

我的JSON数据如下所示：

[
    {
        "email":"test@test.com",
        "firstName":"test",
        "lastName":"test",
        "value":"test@test.com",
        "tokens":"test@test.com"
    },
    {
        ...
    }
]

和用于创建json文件的php数据如下所示：

<?php
    session_start();
    include('connection.php');
    $userId = $_SESSION['sess_user_id'];
    $act = $_POST['action'];
    $sth = mysql_query("SELECT email, firstName, lastName, email AS value, email AS tokens FROM User");
    $rows = array();
    while($r = mysql_fetch_assoc($sth))
    {
        $rows[] = $r;
    }
    $fp = fopen('./test.json', 'w');
    fwrite($fp, json_encode($rows));
    fclose($fp);
?>

当用户被添加到数据库时，它运行这个PHP代码：

$file = './test.json';
$data = json_decode(file_get_contents($file), true);
$newdata = array('email'=>$email, 'firstName' => $firstName, 'lastName'=>$lastName, 'value'=>$email, 'tokens'=>$email);
$data[] = $newdata;
file_put_contents($file, json_encode($data));

我希望我的JSON文件看起来像这样：

[
    {
        "email":"test@test.com",
        "firstName":"test",
        "lastName":"test",
        "value":"test@test.com",
        "tokens":[
            "test@test.com"
        ]
    }
]

我试图解决这个问题，但我做不到。请帮帮忙？

Answer 1

php处理与javascript不同的数组（区分对象和数组）。

$newdata = array(
    'email'=>$email, 
    'firstName' => $firstName, 
    'lastName'=>$lastName, 
    'value'=>$email, 
    'tokens'=>array($email)
);

应该这样做。

如何使用PHP创建JSON数组

1 个答案: