假设我有以下表格：
BrandsTable
+-----------+--------------+------+-----+---------+-------+
| Field | Type | Null | Key | Default | Extra |
+-----------+--------------+------+-----+---------+-------+
| ID | varchar(20) | NO | PRI | NULL | |
| CarBrand | varchar(100) | NO | | NULL | |
| FuelType | varchar(100) | NO | | NULL | |
+-----------+--------------+------+-----+---------+-------+
ModelsTable
+------------+--------------+------+-----+---------+-------+
| Field | Type | Null | Key | Default | Extra |
+------------+--------------+------+-----+---------+-------+
| ID | int(2) | NO | | NULL | |
| Model | varchar(100) | NO | | NULL | |
| BrandID | varchar(100) | NO | MUL | NULL | |
| TopSpeed | varchar(100) | NO | | NULL | |
+------------+--------------+------+-----+---------+-------+
以下是一些条目
+----+----------------+-------------------------+
| ID | CarBrand | FuelType |
+----+----------------+-------------------------+
| 0 | Ford | Gasoline |
| 1 | Chevy | Gasoline |
| 2 | Peterbilt | Diesel |
| 3 | GMC | Gasoline |
| 4 | OshKosh | Natural Gas |
+----+----------------+-------------------------+
+----+---------------+---------+------------+
| ID | Model | BrandID | TopSpeed |
+----+---------------+---------+------------+
| 1 | F150 | 0 | 130MPH |
| 2 | 1500 | 1 | 110MPH |
| 3 | 389 | 2 | 70MPH |
| 4 | 1500 | 3 | 110MPH |
| 5 | Mustang | 0 | 170MPH |
| 6 | Cement Truck | 4 | 65MPH |
+----+---------------+---------+------------+
Models表中的BrandID列是Brand表的主键ID列的外键。如果您无法访问任何一列的值，该怎么办？我将如何编写一个SQL查询，该查询将使用INNER JOIN列出所有属于Ford的模型
答案 0 :(得分：1)
没有访问ID，这意味着你只有我猜的模型名称.. 所以知道“福特”你可以得到这样的两个ids ......
select * from modelsTable Mod inner join brandsTable Bra
on Mod.id= ( select id from Bra where CarBrand='FORD')