必须为JOIN表达式定义标识变量

Question

大家好我得到了错误

[57, 57] An identification variable must be defined for a JOIN expression

尝试运行此查询时

    public String searchString = "test";

    public List<Appointment> appointmentRangeSearch(Date startdatetime, Date endDate) {
        Query q = em.createQuery("SELECT u FROM Appointment U INNER JOIN Users_appointment "
                + "ON u.userid = users_appointment.userid"
                + " WHERE u.startDatetime BETWEEN :date1 AND :date2 "
                + "AND u.ATTENDEES_USER_NAME LIKE :search");
//Query q = em.createQuery("SELECT u FROM Appointment U WHERE u.startDatetime BETWEEN :date1 AND :date2");
        q.setParameter("search", "%" + searchString + "%");
        q.setParameter("date1", startdatetime, TemporalType.TIMESTAMP);
        q.setParameter("date2", endDate, TemporalType.TIMESTAMP);
        return q.getResultList();
    }

是什么导致了这个？以及如何修复

谢谢！

Answer 1

也许，因为你有不同的表名：

INNER JOIN Users_appointment

和

users_appointment.userid

Answer 2

看不出任何错误...尝试制作U小写并使用

SELECT u。* FROM Appointment u ....

em.createQuery("SELECT u.* FROM Appointment u INNER JOIN Users_appointment "
                + "ON u.userid = users_appointment.userid"
                + " WHERE u.startDatetime BETWEEN :date1 AND :date2 "
                + "AND u.ATTENDEES_USER_NAME LIKE :search");