Question

示例很清楚，我有一个继承deque的类和一个模块'collections'的方法，有时候我使用defaultdict，有些则没有。

>>> from collections import deque, defaultdict
>>> import pickle
>>> class lista(deque):
...         def __init__(self):
...             deque.__init__(self)
...             self.lib = defaultdict(dict)
... 
>>> p = lista()
>>> p.append("a")
>>> p.append("b")
>>> p.lib['t']=0
>>> p.__reduce__()
(<class '__main__.lista'>, (['a', 'b'], None), {'lib': defaultdict(<type 'dict'>, {'t': 0})})
>>> pik = pickle.dumps(p)
>>> unpik = pickle.loads(pik)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/pickle.py", line 1382, in loads
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/pickle.py", line 858, in load
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/pickle.py", line 1133, in load_reduce
TypeError: __init__() takes exactly 1 argument (3 given)
>>>

最后一个问题，如何序列化这个对象？

Answer 1

Deque是initialized with up to 3 args：

class collections.deque([iterable[, maxlen]])

虽然提供了unpickling，但提供了所有三个（包括self），而__init__则不接受它们。例如更改为

class lista(deque):
    def __init__(self, iterable=(), maxlen=None):
        deque.__init__(self, iterable, maxlen)
        self.lib = defaultdict(dict)

如何挑选一个继承自collections.deque的类？

1 个答案: