我的网站上有2台打字机插件。两者都在同一个盒子里。首先,它只键入一个句子,第二个句子有4个句子,并且在第二个句子出现之前擦除一个句子。如何在第一台打字机完成后启动第二台打字机“类型”?
<script type="text/javascript">
$(function() {
var text = $(".js-typewrite").text();
var stop = text.length;
var count = "0";
$(".js-typewrite").text("");
var type = function() {
count++;
if (count <= stop) {
$(".js-typewrite").text(text.substr(0, count));
} else {
var write = clearInterval(type);
}
}
var write = setInterval(type, 60);
});
</script>
<script type="text/javascript">
var TxtType = function(el, toRotate, period) {
this.toRotate = toRotate;
this.el = el;
this.loopNum = 0;
this.period = parseInt(period, 10) || 2000;
this.txt = '';
this.tick();
this.isDeleting = false;
};
TxtType.prototype.tick = function() {
var i = this.loopNum % this.toRotate.length;
var fullTxt = this.toRotate[i];
if (this.isDeleting) {
this.txt = fullTxt.substring(0, this.txt.length - 1);
} else {
this.txt = fullTxt.substring(0, this.txt.length + 1);
}
this.el.innerHTML = '<span class="wrap">' + this.txt + '</span>';
var that = this;
var delta = 100 - Math.random() * 100;
if (this.isDeleting) {
delta /= 2;
}
if (!this.isDeleting && this.txt === fullTxt) {
delta = this.period;
this.isDeleting = true;
} else if (this.isDeleting && this.txt === '') {
this.isDeleting = false;
this.loopNum++;
delta = 500;
}
setTimeout(function() {
that.tick();
}, delta );
};
window.onload = function() {
var elements = document.getElementsByClassName('typewrite');
for (var i = 0; i < elements.length; i++) {
var toRotate = elements[i].getAttribute('data-type');
var period = elements[i].getAttribute('data-period');
if (toRotate) {
new TxtType(elements[i], JSON.parse(toRotate), period);
}
}
// INJECT CSS
var css = document.createElement("style");
css.type = "text/css";
css.innerHTML = "";
document.body.appendChild(css);
};
</script>
答案 0 :(得分:0)
使用setTimeout
来延迟并在时间间隔之后调用一个函数。
语法:
setTimeout(function(){
//your code here
})},2000);
// 2000是2秒延迟
答案 1 :(得分:0)
如果您使用的是jQuery,请尝试使用jQuery.defered或defered.promise