Question

下面是使用proc_open运行程序（test.exe-代码）的php脚本。它只是挂在浏览器中。测试程序没有将这两个文件写入目录。但是如果我取出stream_get_contents行并在写入STDIN之后将其添加进去，它就会回显STDOUT。这两个文件都没有写，但我不明白为什么。有什么建议？编辑：echo fgetc($pipes[1]);不阻止......嗯

<?
test(234);

function test($number) {
  $descriptorspec = array(
     0 => array("pipe", "r"),  // stdin is a pipe that the child will read from
     1 => array("pipe", "w"),  // stdout is a pipe that the child will write to
     2 => array("file","whatever.log", "a") // stderr is a file to write to
  );

    $process = proc_open("cd \"C:/\" && test.exe", $descriptorspec, $pipes);

if (is_resource($process)) {
echo stream_get_contents($pipes[1]);
fclose($pipes[1]);

fwrite($pipes[0],$number);
fclose($pipes[0]);

    return !$return_value;
  }
}
?>

C程序（按预期从cmdline工作）：

#include<stdio.h>

void main()
{
int i;
FILE *ofp;

printf("Please enter an integer number");
fflush ( stdout );
scanf("%d", &i);

ofp = fopen("test.txt", "w");
fprintf(ofp, "%d", i);
fclose(ofp);
}

Answer 1

想通了：你需要在Windows上为freads指定缓冲区：

echo fread($pipes[1], 1024);

proc_open不在简单的C程序上写入STDIN

1 个答案: