SQL:返回列包含给定值的列名

时间:2013-12-05 16:26:41

标签: sql sql-server-2012

我想知道是否有一个命令/存储过程可以在SQL Server中运行,它将为我提供包含表中给定数据的列的名称。

所以,如果我要查询,请给我这个表中包含值75的所有列。我不想要该行。只是表格中的列名...这可能吗?

2 个答案:

答案 0 :(得分:2)

-- input parameters (guessing on type for @value):

DECLARE 
  @schema SYSNAME = N'dbo', 
  @table  SYSNAME = N'z', 
  @value  VARCHAR(64) = '75';


-- now, inside the procedure body:

DECLARE @sql NVARCHAR(MAX) = N'SELECT ''cols:'' + STUFF(''''';

SELECT @sql += N' 
  + CASE WHEN EXISTS (SELECT 1 FROM ' 
  + QUOTENAME(@schema) + '.' + QUOTENAME(@table)
  + ' WHERE TRY_CONVERT(VARCHAR(64), ' + QUOTENAME(c.name) 
  + ') = @value) THEN '', ' + c.name + ''' ELSE '''' END'
FROM sys.tables AS t
INNER JOIN sys.columns AS c
ON t.[object_id] = c.[object_id]
INNER JOIN sys.schemas AS s
ON t.[schema_id] = s.[schema_id]
WHERE t.name = @table AND s.name = @schema;

SET @sql += N', 1, 1, '''');'

PRINT @sql;

--EXEC sp_executesql @sql, N'@value VARCHAR(64)', @value;

如果您对输出感到满意,请取消注释EXEC

所以让我们考虑一个简单的表格:

CREATE TABLE dbo.floob
(
  a INT, 
  b VARCHAR(32), 
  c VARBINARY(22), 
  d DATE, 
  e DATETIME, 
  f ROWVERSION
);

INSERT dbo.floob(a,b,c,d,e) VALUES
( 75, 'foo', 0x00, GETDATE(), GETDATE()),
( 21, '75',  0x00, GETDATE(), GETDATE());

现在,基于以上代码的存储过程:

CREATE PROCEDURE dbo.FindStringInAnyColumn
  @schema SYSNAME = N'dbo', 
  @table  SYSNAME,
  @value  VARCHAR(64)
AS
BEGIN
  SET NOCOUNT ON;

  DECLARE @sql NVARCHAR(MAX) = N'SELECT ''cols:'' + STUFF(''''';

  SELECT @sql += N' 
    + CASE WHEN EXISTS (SELECT 1 FROM ' 
    + QUOTENAME(@schema) + '.' + QUOTENAME(@table)
    + ' WHERE TRY_CONVERT(VARCHAR(64), ' + QUOTENAME(c.name) 
    + ') = @value) THEN '', ' + c.name + ''' ELSE '''' END'
  FROM sys.tables AS t
  INNER JOIN sys.columns AS c
  ON t.[object_id] = c.[object_id]
  INNER JOIN sys.schemas AS s
  ON t.[schema_id] = s.[schema_id]
  WHERE t.name = @table AND s.name = @schema;

  SET @sql += N', 1, 1, '''');'

  EXEC sp_executesql @sql, N'@value VARCHAR(64)', @value;
END
GO

样本用法:

EXEC dbo.FindStringInAnyColumn @table = N'floob', @value = '75';

输出:

Cols: a, b

答案 1 :(得分:0)

我同意上述评论,听起来你有一个次优的架构设计。如果您尝试在大型数据集上执行此操作,则可能会遇到性能问题。

也就是说,您可以将列展开以将其转换为行。以下是从Technet上的Using PIVOT and UNPIVOT文章中逐字解读的示例。而不是75,我用了4:

--Create the table and insert values as portrayed in the previous example.
CREATE TABLE pvt (VendorID int, Emp1 int, Emp2 int,
    Emp3 int, Emp4 int, Emp5 int);
GO
INSERT INTO pvt VALUES (1,4,3,5,4,4);
INSERT INTO pvt VALUES (2,4,1,5,5,5);
INSERT INTO pvt VALUES (3,4,3,5,4,4);
INSERT INTO pvt VALUES (4,4,2,5,5,4);
INSERT INTO pvt VALUES (5,5,1,5,5,5);
GO
--Unpivot the table.
SELECT VendorID, Employee, Orders
FROM 
   (SELECT VendorID, Emp1, Emp2, Emp3, Emp4, Emp5
   FROM pvt) p
UNPIVOT
   (Orders FOR Employee IN 
      (Emp1, Emp2, Emp3, Emp4, Emp5)
)AS unpvt
WHERE VendorID = 1 AND orders = 4;

这产生以下结果:

+--+----------------------------------------+
|  | VendorID        Employee        Orders |
+--+----------------------------------------+
|  | 1               Emp1            4      |
|  | 1               Emp4            4      |
|  | 1               Emp5            4      |
+--+----------------------------------------+