Question

我正在努力处理一段代码。我已经知道了此代码出错。它使用cURL。卷曲过程有效但是我已经添加了一个if语句来检查逻辑为了将某些变量传递给其他服务器。提前谢谢..

<?php
    include("../config.php");

    if ( !isset( $_COOKIE['admin'] ) ) {

    include_once("login.php");
    echo ("<div id='quote'>Error: Can not access page.");
    }
    else {
    if (isset($_GET['user']) && ($_GET['user'] != "") && isset($_GET['licence']) && ($_GET['licence'] != "") &&
    isset($_GET['to']) && ($_GET['to'] != "") && ($_GET['username'] !=
    "")) {
    $username = $_GET["username"]; 
    $idlisc= $_GET["user"];
    $licence = $_GET["licence"];
    $to = $_GET["to"];

    $acc = new Account;
    $acc->changeVis($idlisc, $licence, $to);
    header("Location: search.php?user=".$username); 

    if ($get["lic_".$i.] == 11 || 12 || 13 || 14 || 15 || 16 || 17 || 18 || 19 || 20) {

    $ch = curl_init(); //http post to another server

    curl_setopt($ch, CURLOPT_URL,"http://xxx/add-user");
    curl_setopt($ch, CURLOPT_POST, 1);
    curl_setopt($ch, CURLOPT_POSTFIELDS,
            "codes=$licence");

        // receive server response ...
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);

    $server_output = curl_exec ($ch);

    print_r($server_output);

    curl_close ($ch);
    }
    else {
    $ch = curl_init(); //http post to another server

    curl_setopt($ch, CURLOPT_URL,"http://xxx/add-user");
    curl_setopt($ch, CURLOPT_POST, 1);
    curl_setopt($ch, CURLOPT_POSTFIELDS,
            "usr=$username&code=$licence&password=$id");

        // receive server response ...
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);

    $server_output = curl_exec ($ch);

    print_r($server_output);

    curl_close ($ch);


    }


    }

Answer 1

你有两个语法错误

if ($_get["lic_".$i.]
     -------------^ // Remove this dot

第二，你需要在代码的最后关闭一个大括号

curl_close ($ch);
  }
 }
} //<---- Add a brace here

编辑：

检查您的 if 语句是否符合此

if ($_get["lic_".$i] == 11 || 12 || 13 || 14 || 15 || 16 || 17 || 18 || 19 || 20)

我的PHP代码语法错误

1 个答案: