我正在一个名为 Customer_page.java 的活动的表中创建和插入数据,代码如下:
db= openOrCreateDatabase("dsr", MODE_PRIVATE, null);
db.execSQL("create table if not exists customer_form" +
"(id INTEGER PRIMARY KEY AUTOINCREMENT," +
"sales_person TEXT,current_date Text,contact_person TEXT, contact_number TEXT, distance TEXT, description TEXT," +
"location TEXT, type_of_meeting TEXT,interest TEXT, time_in TEXT, time_out TEXT, flag INTEGER)"
);
并插入如下数据:
db.execSQL("insert into customer_form(sales_person,current_date,contact_person,contact_number,distance,description,"+
"location,type_of_meeting,interest,time_in,time_out,flag) values" +
"('null',date('now'),'"+contact_person+"','"+contact_number+"','"+distance+"','"+description+"','"+location+"','"+type_of_meeting+"','"+interested+"',"+
"'"+time_in+"','"+time_out+"',0)");
现在我正在更新 Welcome.java 活动中的customer_form表,代码如下:
db=openOrCreateDatabase("dsr", MODE_PRIVATE, null);
db.execSQL("update customer_form set sales_person='"+email_id+"' where sales_person='null'");
db.close();
但是这段代码没有更新表而且没有给出任何错误。如何在 Welcome.java 活动中更新customer_form表?
答案 0 :(得分:2)
我使用下面给出的代码:
首先我创建了一个新类 Database_Update.java
package com.example.hello;
import android.content.Context;
import android.database.sqlite.SQLiteDatabase;
import android.database.sqlite.SQLiteOpenHelper;
public class Database_Update extends SQLiteOpenHelper{
private static final String DB_NAME="dsr";
private static final int DB_VER=1;
public Database_Update(Context context) {
super(context,DB_NAME, null, DB_VER);
}
@Override
public void onCreate(SQLiteDatabase database) {
}
@Override
public void onUpgrade(SQLiteDatabase database, int arg1, int arg2) {
onCreate(database);
}
}
然后在我的新活动中访问表以进行更新:
Database_Update du=new Database_Update(this);
SQLiteDatabase sd=du.getReadableDatabase();
ContentValues value=new ContentValues();
value.put("sales_person", email_id);
int updated=sd.update("customer_form", value, "sales_person='no_value'", null);
答案 1 :(得分:0)
您可以使用"update customer_form set sales_person='"+email_id+"' where sales_person IS NULL OR sales_person=''"