如何使用ScheduledExecutorService在特定时间每天运行某些任务?

时间:2013-12-04 22:56:47

标签: java timertask background-thread scheduledexecutorservice

我每天凌晨5点都要尝试完成某项任务。所以我决定使用ScheduledExecutorService,但到目前为止,我已经看到了一些示例,显示了如何每隔几分钟运行一次任务。

我无法找到任何显示如何在早上的特定时间(早上5点)每天运行任务的例子,同时也考虑夏令时的事实 -

以下是我的代码,每15分钟运行一次 -

public class ScheduledTaskExample {
    private final ScheduledExecutorService scheduler = Executors
        .newScheduledThreadPool(1);

    public void startScheduleTask() {
    /**
    * not using the taskHandle returned here, but it can be used to cancel
    * the task, or check if it's done (for recurring tasks, that's not
    * going to be very useful)
    */
    final ScheduledFuture<?> taskHandle = scheduler.scheduleAtFixedRate(
        new Runnable() {
            public void run() {
                try {
                    getDataFromDatabase();
                }catch(Exception ex) {
                    ex.printStackTrace(); //or loggger would be better
                }
            }
        }, 0, 15, TimeUnit.MINUTES);
    }

    private void getDataFromDatabase() {
        System.out.println("getting data...");
    }

    public static void main(String[] args) {
        ScheduledTaskExample ste = new ScheduledTaskExample();
        ste.startScheduleTask();
    }
}

有什么办法,考虑到夏令时的事实,我可以使用ScheduledExecutorService安排每天凌晨5点运行任务吗?

而且TimerTask对此更好或ScheduledExecutorService

13 个答案:

答案 0 :(得分:76)

与目前的Java SE 8版本一样,它具有java.time的优秀日期时间API,可以更轻松地完成这些计算,而不是使用java.util.Calendarjava.util.Date

现在作为使用您的用例安排任务的示例示例:

ZonedDateTime now = ZonedDateTime.now(ZoneId.of("America/Los_Angeles"));
ZonedDateTime nextRun = now.withHour(5).withMinute(0).withSecond(0);
if(now.compareTo(nextRun) > 0)
    nextRun = nextRun.plusDays(1);

Duration duration = Duration.between(now, nextRun);
long initalDelay = duration.getSeconds();

ScheduledExecutorService scheduler = Executors.newScheduledThreadPool(1);            
scheduler.scheduleAtFixedRate(new MyRunnableTask(),
    initalDelay,
    TimeUnit.DAYS.toSeconds(1),
    TimeUnit.SECONDS);

计算initalDelay以要求调度程序延迟TimeUnit.SECONDS中的执行。对于此用例,单位毫秒及以下的时差问题似乎可以忽略不计。但是您仍然可以使用duration.toMillis()TimeUnit.MILLISECONDS来处理调度计算(以毫秒为单位)。

  

对于这个或者ScheduledExecutorService,TimerTask更好吗?

NO: ScheduledExecutorService似乎比TimerTask更好。 StackOverflow has already an answer for you

来自@PaddyD,

  

您仍然遇到需要每年重启两次的问题   如果你想让它在当地时间运行。 scheduleAtFixedRate   除非你对全年的UTC时间感到满意,否则不会削减它。

事实并且@PaddyD已经给出了一个解决方法(给他+1),我提供了一个带有ScheduledExecutorService的Java8日期时间API的工作示例。 Using daemon thread is dangerous

class MyTaskExecutor
{
    ScheduledExecutorService executorService = Executors.newScheduledThreadPool(1);
    MyTask myTask;
    volatile boolean isStopIssued;

    public MyTaskExecutor(MyTask myTask$) 
    {
        myTask = myTask$;

    }

    public void startExecutionAt(int targetHour, int targetMin, int targetSec)
    {
        Runnable taskWrapper = new Runnable(){

            @Override
            public void run() 
            {
                myTask.execute();
                startExecutionAt(targetHour, targetMin, targetSec);
            }

        };
        long delay = computeNextDelay(targetHour, targetMin, targetSec);
        executorService.schedule(taskWrapper, delay, TimeUnit.SECONDS);
    }

    private long computeNextDelay(int targetHour, int targetMin, int targetSec) 
    {
        LocalDateTime localNow = LocalDateTime.now();
        ZoneId currentZone = ZoneId.systemDefault();
        ZonedDateTime zonedNow = ZonedDateTime.of(localNow, currentZone);
        ZonedDateTime zonedNextTarget = zonedNow.withHour(targetHour).withMinute(targetMin).withSecond(targetSec);
        if(zonedNow.compareTo(zonedNextTarget) > 0)
            zonedNextTarget = zonedNextTarget.plusDays(1);

        Duration duration = Duration.between(zonedNow, zonedNextTarget);
        return duration.getSeconds();
    }

    public void stop()
    {
        executorService.shutdown();
        try {
            executorService.awaitTermination(1, TimeUnit.DAYS);
        } catch (InterruptedException ex) {
            Logger.getLogger(MyTaskExecutor.class.getName()).log(Level.SEVERE, null, ex);
        }
    }
}

注意:

  • MyTask是功能execute的接口。
  • 在停止ScheduledExecutorService时,在调用awaitTermination之后始终使用shutdown:您的任务总是有可能卡住/死锁,用户会永远等待。

我之前用Calender提供的示例只是一个想法我提到过,我避免了精确的时间计算和夏令时问题。根据@PaddyD

的抱怨更新了解决方案

答案 1 :(得分:18)

在Java 8中:

scheduler = Executors.newScheduledThreadPool(1);

//Change here for the hour you want ----------------------------------.at()       
Long midnight=LocalDateTime.now().until(LocalDate.now().plusDays(1).atStartOfDay(), ChronoUnit.MINUTES);
scheduler.scheduleAtFixedRate(this, midnight, 1440, TimeUnit.MINUTES);

答案 2 :(得分:7)

如果您没有能力使用Java 8,那么以下内容将满足您的需求:

public class DailyRunnerDaemon
{
   private final Runnable dailyTask;
   private final int hour;
   private final int minute;
   private final int second;
   private final String runThreadName;

   public DailyRunnerDaemon(Calendar timeOfDay, Runnable dailyTask, String runThreadName)
   {
      this.dailyTask = dailyTask;
      this.hour = timeOfDay.get(Calendar.HOUR_OF_DAY);
      this.minute = timeOfDay.get(Calendar.MINUTE);
      this.second = timeOfDay.get(Calendar.SECOND);
      this.runThreadName = runThreadName;
   }

   public void start()
   {
      startTimer();
   }

   private void startTimer();
   {
      new Timer(runThreadName, true).schedule(new TimerTask()
      {
         @Override
         public void run()
         {
            dailyTask.run();
            startTimer();
         }
      }, getNextRunTime());
   }


   private Date getNextRunTime()
   {
      Calendar startTime = Calendar.getInstance();
      Calendar now = Calendar.getInstance();
      startTime.set(Calendar.HOUR_OF_DAY, hour);
      startTime.set(Calendar.MINUTE, minute);
      startTime.set(Calendar.SECOND, second);
      startTime.set(Calendar.MILLISECOND, 0);

      if(startTime.before(now) || startTime.equals(now))
      {
         startTime.add(Calendar.DATE, 1);
      }

      return startTime.getTime();
   }
}

它不需要任何外部库,并将考虑夏令时。只需将您想要作为Calendar对象运行任务的时间传递给Runnable。例如:

Calendar timeOfDay = Calendar.getInstance();
timeOfDay.set(Calendar.HOUR_OF_DAY, 5);
timeOfDay.set(Calendar.MINUTE, 0);
timeOfDay.set(Calendar.SECOND, 0);

new DailyRunnerDaemon(timeOfDay, new Runnable()
{
   @Override
   public void run()
   {
      try
      {
        // call whatever your daily task is here
        doHousekeeping();
      }
      catch(Exception e)
      {
        logger.error("An error occurred performing daily housekeeping", e);
      }
   }
}, "daily-housekeeping");

N.B。计时器任务在守护程序线程中运行,不建议执行任何IO。如果需要使用User线程,则需要添加另一个取消计时器的方法。

如果您必须使用ScheduledExecutorService,只需将startTimer方法更改为以下内容:

private void startTimer()
{
   Executors.newSingleThreadExecutor().schedule(new Runnable()
   {
      Thread.currentThread().setName(runThreadName);
      dailyTask.run();
      startTimer();
   }, getNextRunTime().getTime() - System.currentTimeMillis(),
   TimeUnit.MILLISECONDS);
}

我不确定该行为,但如果您沿着shutdownNow路线走,可能需要一个调用ScheduledExecutorService的停止方法,否则当您尝试停止时,您的应用可能会挂起。

答案 3 :(得分:5)

您是否考虑使用Quartz Scheduler之类的内容?这个库有一个机制,可以使用类似cron的表达式来安排每天在设定的时间段内运行的任务(看看CronScheduleBuilder)。

一些示例代码(未经测试):

public class GetDatabaseJob implements InterruptableJob
{
    public void execute(JobExecutionContext arg0) throws JobExecutionException
    {
        getFromDatabase();
    }
}

public class Example
{
    public static void main(String[] args)
    {
        JobDetails job = JobBuilder.newJob(GetDatabaseJob.class);

        // Schedule to run at 5 AM every day
        ScheduleBuilder scheduleBuilder = 
                CronScheduleBuilder.cronSchedule("0 0 5 * * ?");
        Trigger trigger = TriggerBuilder.newTrigger().
                withSchedule(scheduleBuilder).build();

        Scheduler scheduler = StdSchedulerFactory.getDefaultScheduler();
        scheduler.scheduleJob(job, trigger);

        scheduler.start();
    }
}

前期还有一些工作要做,您可能需要重写您的作业执行代码,但它应该可以让您更好地控制您希望作业运行的方式。如果需要,也可以更容易地更改时间表。

答案 4 :(得分:5)

Java8:
我的升级版本来自顶部答案:

  1. 修复Web应用服务器因为线程池空闲线程而无法停止的情况
  2. 没有递归
  3. 使用您的自定义本地时间运行任务,就我而言,白俄罗斯,明斯克

  4. /**
     * Execute {@link AppWork} once per day.
     * <p>
     * Created by aalexeenka on 29.12.2016.
     */
    public class OncePerDayAppWorkExecutor {
    
        private static final Logger LOG = AppLoggerFactory.getScheduleLog(OncePerDayAppWorkExecutor.class);
    
        private ScheduledExecutorService executorService = Executors.newScheduledThreadPool(1);
    
        private final String name;
        private final AppWork appWork;
    
        private final int targetHour;
        private final int targetMin;
        private final int targetSec;
    
        private volatile boolean isBusy = false;
        private volatile ScheduledFuture<?> scheduledTask = null;
    
        private AtomicInteger completedTasks = new AtomicInteger(0);
    
        public OncePerDayAppWorkExecutor(
                String name,
                AppWork appWork,
                int targetHour,
                int targetMin,
                int targetSec
        ) {
            this.name = "Executor [" + name + "]";
            this.appWork = appWork;
    
            this.targetHour = targetHour;
            this.targetMin = targetMin;
            this.targetSec = targetSec;
        }
    
        public void start() {
            scheduleNextTask(doTaskWork());
        }
    
        private Runnable doTaskWork() {
            return () -> {
                LOG.info(name + " [" + completedTasks.get() + "] start: " + minskDateTime());
                try {
                    isBusy = true;
                    appWork.doWork();
                    LOG.info(name + " finish work in " + minskDateTime());
                } catch (Exception ex) {
                    LOG.error(name + " throw exception in " + minskDateTime(), ex);
                } finally {
                    isBusy = false;
                }
                scheduleNextTask(doTaskWork());
                LOG.info(name + " [" + completedTasks.get() + "] finish: " + minskDateTime());
                LOG.info(name + " completed tasks: " + completedTasks.incrementAndGet());
            };
        }
    
        private void scheduleNextTask(Runnable task) {
            LOG.info(name + " make schedule in " + minskDateTime());
            long delay = computeNextDelay(targetHour, targetMin, targetSec);
            LOG.info(name + " has delay in " + delay);
            scheduledTask = executorService.schedule(task, delay, TimeUnit.SECONDS);
        }
    
        private static long computeNextDelay(int targetHour, int targetMin, int targetSec) {
            ZonedDateTime zonedNow = minskDateTime();
            ZonedDateTime zonedNextTarget = zonedNow.withHour(targetHour).withMinute(targetMin).withSecond(targetSec).withNano(0);
    
            if (zonedNow.compareTo(zonedNextTarget) > 0) {
                zonedNextTarget = zonedNextTarget.plusDays(1);
            }
    
            Duration duration = Duration.between(zonedNow, zonedNextTarget);
            return duration.getSeconds();
        }
    
        public static ZonedDateTime minskDateTime() {
            return ZonedDateTime.now(ZoneId.of("Europe/Minsk"));
        }
    
        public void stop() {
            LOG.info(name + " is stopping.");
            if (scheduledTask != null) {
                scheduledTask.cancel(false);
            }
            executorService.shutdown();
            LOG.info(name + " stopped.");
            try {
                LOG.info(name + " awaitTermination, start: isBusy [ " + isBusy + "]");
                // wait one minute to termination if busy
                if (isBusy) {
                    executorService.awaitTermination(1, TimeUnit.MINUTES);
                }
            } catch (InterruptedException ex) {
                LOG.error(name + " awaitTermination exception", ex);
            } finally {
                LOG.info(name + " awaitTermination, finish");
            }
        }
    
    }
    

答案 5 :(得分:2)

我有类似的问题。我必须使用ScheduledExecutorService安排一天中应该执行的一系列任务。 这是通过从凌晨3:30开始的一项任务解决的,相对于他的当前时间安排所有其他任务。并在第二天凌晨3:30重新安排自己。

在这种情况下,夏令时不再是问题。

答案 6 :(得分:1)

你可以使用一个简单的日期解析,如果现在的时间是在现在之前,让我们明天开始:

  String timeToStart = "12:17:30";
  SimpleDateFormat format = new SimpleDateFormat("yyyy-MM-dd 'at' HH:mm:ss");
  SimpleDateFormat formatOnlyDay = new SimpleDateFormat("yyyy-MM-dd");
  Date now = new Date();
  Date dateToStart = format.parse(formatOnlyDay.format(now) + " at " + timeToStart);
  long diff = dateToStart.getTime() - now.getTime();
  if (diff < 0) {
    // tomorrow
    Date tomorrow = new Date();
    Calendar c = Calendar.getInstance();
    c.setTime(tomorrow);
    c.add(Calendar.DATE, 1);
    tomorrow = c.getTime();
    dateToStart = format.parse(formatOnlyDay.format(tomorrow) + " at " + timeToStart);
    diff = dateToStart.getTime() - now.getTime();
  }

  ScheduledExecutorService scheduler = Executors.newScheduledThreadPool(1);            
  scheduler.scheduleAtFixedRate(new MyRunnableTask(), TimeUnit.MILLISECONDS.toSeconds(diff) ,
                                  24*60*60, TimeUnit.SECONDS);

答案 7 :(得分:1)

只需添加Victor's answer

我建议添加一个检查,看看变量(在他的情况下是长midnight)是否高于1440。如果是,我会省略.plusDays(1),否则任务只会在后天运行。

我这样做就是这样:

Long time;

final Long tempTime = LocalDateTime.now().until(LocalDate.now().plusDays(1).atTime(7, 0), ChronoUnit.MINUTES);
if (tempTime > 1440) {
    time = LocalDateTime.now().until(LocalDate.now().atTime(7, 0), ChronoUnit.MINUTES);
} else {
    time = tempTime;
}

答案 8 :(得分:1)

以下示例对我有用

public class DemoScheduler {

    public static void main(String[] args) {

        // Create a calendar instance
        Calendar calendar = Calendar.getInstance();

        // Set time of execution. Here, we have to run every day 4:20 PM; so,
        // setting all parameters.
        calendar.set(Calendar.HOUR, 8);
        calendar.set(Calendar.MINUTE, 0);
        calendar.set(Calendar.SECOND, 0);
        calendar.set(Calendar.AM_PM, Calendar.AM);

        Long currentTime = new Date().getTime();

        // Check if current time is greater than our calendar's time. If So,
        // then change date to one day plus. As the time already pass for
        // execution.
        if (calendar.getTime().getTime() < currentTime) {
            calendar.add(Calendar.DATE, 1);
        }

        // Calendar is scheduled for future; so, it's time is higher than
        // current time.
        long startScheduler = calendar.getTime().getTime() - currentTime;

        // Setting stop scheduler at 4:21 PM. Over here, we are using current
        // calendar's object; so, date and AM_PM is not needed to set
        calendar.set(Calendar.HOUR, 5);
        calendar.set(Calendar.MINUTE, 0);
        calendar.set(Calendar.AM_PM, Calendar.PM);

        // Calculation stop scheduler
        long stopScheduler = calendar.getTime().getTime() - currentTime;

        // Executor is Runnable. The code which you want to run periodically.
        Runnable task = new Runnable() {

            @Override
            public void run() {

                System.out.println("test");
            }
        };

        // Get an instance of scheduler
        final ScheduledExecutorService scheduler = Executors.newScheduledThreadPool(1);
        // execute scheduler at fixed time.
        scheduler.scheduleAtFixedRate(task, startScheduler, stopScheduler, MILLISECONDS);
    }
}

参考: https://chynten.wordpress.com/2016/06/03/java-scheduler-to-run-every-day-on-specific-time/

答案 9 :(得分:0)

您可以使用下面的课程安排每天的特定时间的任务

package interfaces;

import java.time.LocalDate;
import java.time.LocalDateTime;
import java.time.temporal.ChronoUnit;
import java.util.Date;
import java.util.concurrent.Executors;
import java.util.concurrent.ScheduledExecutorService;
import java.util.concurrent.TimeUnit;

public class CronDemo implements Runnable{

    public static void main(String[] args) {

        Long delayTime;

        ScheduledExecutorService scheduler = Executors.newScheduledThreadPool(1);

        final Long initialDelay = LocalDateTime.now().until(LocalDate.now().plusDays(1).atTime(12, 30), ChronoUnit.MINUTES);

        if (initialDelay > TimeUnit.DAYS.toMinutes(1)) {
            delayTime = LocalDateTime.now().until(LocalDate.now().atTime(12, 30), ChronoUnit.MINUTES);
        } else {
            delayTime = initialDelay;
        }

        scheduler.scheduleAtFixedRate(new CronDemo(), delayTime, TimeUnit.DAYS.toMinutes(1), TimeUnit.MINUTES);

    }

    @Override
    public void run() {
        System.out.println("I am your job executin at:" + new Date());
    }
}

答案 10 :(得分:0)

如果您的服务器在4:59 AM停机并在5:01 AM回来,该怎么办?我认为它只会跳过运行。我建议像Quartz这样的持久性调度程序,它将其调度数据存储在某个地方。然后它将看到尚未执行此运行,并将在上午5:01进行。

答案 11 :(得分:0)

如果你可以这样写,为什么要把情况复杂化? (是的 -> 低内聚,硬编码 -> 但它是一个例子,不幸的是使用命令方式)。有关更多信息,请阅读下面的代码示例;))

package timer.test;

import org.slf4j.Logger;
import org.slf4j.LoggerFactory;

import java.time.Duration;
import java.time.LocalDate;
import java.time.LocalDateTime;
import java.util.concurrent.*;

public class TestKitTimerWithExecuterService {

    private static final Logger log = LoggerFactory.getLogger(TestKitTimerWithExecuterService.class);

    private static final ScheduledExecutorService executorService 
= Executors.newSingleThreadScheduledExecutor();// equal to => newScheduledThreadPool(1)/ Executor service with one Thread

    private static ScheduledFuture<?> future; // why? because scheduleAtFixedRate will return you it and you can act how you like ;)



    public static void main(String args[]){

        log.info("main thread start");

        Runnable task = () -> log.info("******** Task running ********");

        LocalDateTime now = LocalDateTime.now();

        LocalDateTime whenToStart = LocalDate.now().atTime(20, 11); // hour, minute

        Duration duration = Duration.between(now, whenToStart);

        log.info("WhenToStart : {}, Now : {}, Duration/difference in second : {}",whenToStart, now, duration.getSeconds());

        future = executorService.scheduleAtFixedRate(task
                , duration.getSeconds()    //  difference in second - when to start a job
                ,2                         // period
                , TimeUnit.SECONDS);

        try {
            TimeUnit.MINUTES.sleep(2);  // DanDig imitation of reality
            cancelExecutor();    // after canceling Executor it will never run your job again
        } catch (InterruptedException e) {
            e.printStackTrace();
        }
        log.info("main thread end");
    }




    public static void cancelExecutor(){

        future.cancel(true);
        executorService.shutdown();

        log.info("Executor service goes to shut down");
    }

}

答案 12 :(得分:-1)

这里假设代码在单个 VM 上运行。如果代码在多个 VM 上运行,则此调度程序代码将运行多次。那必须分开处理。