Question

我正在尝试

1）拍摄上传的图像并用枕头将其更改为黑白

2）在视图中将原始文件保存到名为“file”的FileField

3）在视图中将黑白版本保存到ImageField，名为“thumbnail_225”

1和2工作得很好，但我似乎无法弄清楚＃3。

非常感谢任何反馈。

查看

def archive_media_upload(request):

    if request.method == 'POST':
        form = UploadForm(request.POST, request.FILES)
        if form.is_valid():
            m = form.save(commit=False)

            m.user = request.user
            m.type = 1

                        # create black and white
            image = Image.open(m.file)
            black_and_white = image.convert("L")

                        #HOW DO I SAVE/ASSIGN BW IMAGE TO the "thumbnail_225" ImageField?

            m.save()

            return HttpResponseRedirect(reverse('archive_media_archive'))

    else:
        form = UploadForm(initial={'user': request.user })

    return render(request, 'archive_app/archive_media_upload.html', {'archive':True, 'show_upgrade_link': show_upgrade_link,'form': form})

模型

class Media(models.Model):
    created_date = models.DateTimeField(default=datetime.now)
    type = models.IntegerField(default=0)

    user = models.ForeignKey(User)

    title = models.CharField(max_length=255, blank=True)
    file = models.FileField(upload_to=get_upload_file_name)

    thumbnail_225 = models.ImageField(upload_to="thumbnail_images/", blank=True)

Answer 1

为了简短起见，您正在寻找的是（我认为）clean方法。您应该在表单中定义它：

类UploadForm（forms.Form）：

thumbnail_225  = forms.ImageField()

...

def clean_thumbnail_225 (self):
    thumbnail_225 = self.cleaned_data["thumbnail_225"]
    image = Image.open()
    black_and_white = image.convert("thumbnail_225")
    ...
    # return the clean data...

注意上面的代码只是一般方案。它不会真正起作用，也不包含所有正确的逻辑和\或语法。它仅用于演示。完整提示可在DJANGO's form and field validation documentation.

中找到

保存到django imagefield

1 个答案: