Question

我的最后一个问题是从两个表格中建立一个列表。

SELECT CONCAT( P.LastName, ', ', P.FirstName ) AS Name, MP.MembershipID, P.PersonID
FROM `person` P
INNER JOIN `membershipperson` MP ON MP.PersonID = P.PersonID
ORDER BY MP.MembershipID DESC

现在我需要帮助将更多信息添加到列表中。

我需要一个显示 LastName，FirstName，PersonID，MemberID，LastActiveYear，MemberSince，Approved，LockedOut 的列表。
如果 LastActiveYear 是＆lt;
，则批准位为0 2013.我可能想使用一个php mysqli页面，因此我可以根据需要更改年份。

以下是表格示例;

person PersonID LastName FirstName ----------+------------+------------+--------- 1212 Barr Foo 888 To Go 1415 From Is Membershipperson MemberShipID PersonID -------------+------------ 2250 1212 1150 888 3500 1415 users PersonID Username IsApproved LockedOut ----------+-------------+-----------+----------- 1212 2250 1 1 888 1150 1 0 1415 3500 0 1 membership MemberShipId LastActiveYear ---------------+------------------------ #### + 2012

更正并添加了表格。

Answer 1

我假设您要求

我需要一个列表，显示LastName，FirstName，PersonID，MemberID，LastActiveYear，MemberSince，Approved，LockedOut.From评论我需要获取一个LastActiveYear低于2013并且已批准的成员列表位是1

在这里你加入你的人员表会员表和用户表我想你已经保持一对一的关系

SELECT 
p.LastName,
p.FirstName,
p.PersonID, 
m.MemberID, 
p.LastActiveYear, 
p.MemberSince, 
u.Approved,
u.LockedOut
FROM person p
INNER JOIN Membershipperson m ON(m.PersonID = p.PersonID)
INNER JOIN users u ON(u.PersonID = u.PersonID)
INNER JOIN membership ms ON(ms.MembershipId = m.MemberID)
WHERE ms.LastActiveYear < '2013'
AND u.Approved =1
GROUP BY u.PersonID

第二个你要求

sql代码集如果LastActiveYear是＆lt; 2013.我可能想要使用一个php mysqli页面，因此我可以根据需要更改年份。

与在更新查询中加入表并将Approved设置为0

相同

UPDATE users u
INNER JOIN Membershipperson m ON(m.PersonID = u.PersonID)
INNER JOIN  person p ON(p.PersonID = u.PersonID)
INNER JOIN membership ms ON(ms.MembershipId = m.MemberID)
SET u.Approved = 0
WHERE ms.LastActiveYear < '2013'

See Fiddle Updated Fiddle

Answer 2

假设您将使用php mysqli

//Obviously substitute for you mysql credentials
$mysqli_link = mysqli_connect("localhost","root","pas") or die(mysqli_error($mysqli_link));
//again choose the correct right db
mysqli_select_db($mysqli_link,"database") or die (mysqli_error($mysqli_link));


$query = "SELECT CONCAT( P.LastName, ', ', P.FirstName ) AS Name, MP.MembershipID, ms.LastActiveYear, P.PersonID as personId
FROM `person` P
INNER JOIN `membershipperson` MP ON MP.PersonID = P.PersonID
LEFT JOIN `user` ON P.PersonID=users.PersonID
LEFT JOIN `membership` ms ON MP.MemberShipID=ms.MemberShipID
WHERE users.Approved=1
AND ms.LastActiveYear < 2013
ORDER BY MP.MembershipID DESC";

$result = mysqli_query($mysqli_link, $query);

//To see results
$data = array();
$ids = array();
while ($row = mysqli_fetch_assoc($result)) {
    $data[] = $row;
    $ids[] = $row['personId'];

}

echo'<pre>';
print_r($data);
die('</pre>'); // this will stop the rest of the page from loading

//loop through the results and store the `PersonID`'s in an array called `$ids` (or whatever you want to call it)

$ids = implode(',', $ids);
$ids = substr($ids, 0, -1);
$query = "UPDATE users SET Approved=0 WHERE PersonID IN ($ids)";
mysqli_query($mysqli_link, $query);

希望这有帮助！：）

要列出的其他表

2 个答案: