C中的Realloc用于包含动态结构数组的结构

时间:2013-12-04 14:26:52

标签: c dynamic realloc

重新分配项目列表的问题。我试图将项添加到testList结构项中,但我在尝试添加或打印单个ListItems的值时遇到内存地址错误。任何帮助将不胜感激。

struct ListItems
{
    int id;
    int name;
};

struct testList
{
    struct ListItems** items;
    int count;
    int size;
};

struct Test
{
    struct testList* list;
};

void printArray(struct testList* list)
{
    for (int i = 0; i < list->count; i++)
    {
        printf("id=%i, name= %i \n", list->items[i]->id, list->items[i]->name);
        fflush(stdout);
    }
    printf("printing accomplished \n");
    fflush(stdout);
}

void growArray(struct testList* list, struct ListItems* item)
{
    int size = list->size;
    list->items[list->count++] = item;
    struct ListItems** user_array = list->items;
    //printf("array count %i, array size %i \n", list->count, size);
    if (list->size == list->count)
    {
        struct ListItems* temp = realloc(*user_array, (size * 2) * sizeof (struct ListItems));
        if (temp == NULL)
        {
            printf("it's all falling apart! \n");
        }
        else
        {
            *user_array = temp;
            list->size = size * 2;
        }
    }
}

/*
 *
 */
int main(int argc, char** argv)
{

    struct Test* test = (struct Test*) malloc(sizeof (struct Test));
    test->list = (struct testList*) malloc(sizeof (struct testList));
    test->list->count = 0;
    test->list->size = 1;
    test->list->items = (struct ListItems**) malloc(sizeof (struct ListItems*));

    for (int i = 0; i < 32; i++)
    {
        struct ListItems* item = (struct ListItems*) malloc(sizeof (struct ListItems));
        item->id = i;
        item->name = i;
        growArray(test->list, item);
    }
    printArray(test->list);
    for (int j = 0; j < sizeof (test->list->items); j++)
    {
        free(test->list->items[j]);
    }
    free(test->list->items);
    free(test->list);
    free(test);
}

2 个答案:

答案 0 :(得分:0)

您的growArray()需要更新list->items。在当前的代码中,它将永远指向1个元素大小的区域。

编辑:

你的realloc()sizeof (struct ListItems))分配,但指针包含指针,而不是元素。

我会写:

void growArray(struct testList* list, struct ListItems* item)
{
        if (list->size <= list->count) {
              size_t new_size = 2 * list->size;
              struct ListItems** temp = realloc(list->items, new_size * sizeof temp[0]);
              assert(temp);

              list->size = new_size;
              list->items = temp;
        }

        list->items[list->count] = item;
        ++list->count;
}

有了这个,您不需要list->items = malloc(...)中的初始main(),但可以指定NULL

编辑:

for (int j = 0; j < sizeof (test->list->items); j++)

没有意义;你可能想要j < test->list->count

答案 1 :(得分:0)

问题始于struct testList的声明。指向items数组的指针应该只有一个*

struct testList
{
    struct ListItems* items;   // Changed from pointer-to-pointer
    int count;
    int size;
};

这会强制代码中的其他一些更改。